At least they admitted this is algebra not geometry. You'll get the same question next year but they'll call it geometry.
The area is the product of the sides:

We just distribute and collect terms:



Answer: 3rd choice
For this case we must find the point that Harold used to arrive at the following equation:

Starting from the fact that the equation of the point-slope form of a line is given by:

If we compare the standard equation with Harold's, we see that the slope of the line is 
In addition, it is observed that
and 
Then, the correct option is: Harold used the point (7,0)
ANswer:
When Harold wrote his equation, the point was used (7,0).
(4) Halving the value of b
Example #1:
a = 4 , b = 2
x = (4^2) / 2
x = 16 / 2
x = 8
a = 4 , b = 1
x = (4^2) / 1
x = 16 / 1
x = 16
Example #2:
a = 8 , b = 4
x = (8^2) / 4
x = 64 / 4
x = 16
a = 8 , b = 2
x = (8^2) / 2
x = 64 / 2
x = 32
Answer:
62 degrees
Step-by-step explanation:
As two sides shown are same in length thus angle containing by them will be also same.
Thus, other unmarked angle will also be x degrees.
one angle is 56 degrees
we know that sum of angle of triangle is 180 degrees.
Thus
x + x + 56 = 180
2x + 56 = 180
2x = 180 - 56 = 124
x = 124/2 = 62
Thus, value of x is 62 degrees.
Answer:
y = 3/5x - 1
Step-by-step explanation:
The slope found from counting the units is 3/5, and the y-intercept is -1, hence 3/5x - 1