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3 years ago

Which is the formula for nitrogen trihydride? NH3 N3H 3NH N3H3NH3N3H3NHN3H3

Chemistry

2 answers:

kirza4 [7]3 years ago

8 0

Answer:

NH3

Explanation:

The "tri" attached to the trihydride means 3. So your hydrogen is going to have 3 atoms.

krek1111 [17]3 years ago

8 0

Answer:

All Answers only for the elite; Nomenclature of Covalent Compounds Quiz

You're Welcome :)

Explanation:

A-hydrochloric acid

B-sulfuric acid

C-dinitrogen pentoxide

C- IBr3

A- carbon dioxide

B- Start the name with hydro-.

B- H3BO3

C-sulfur trioxide

A- NH3

B- The chemical name ends with “hydroxide.”

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5. What is the systemic name for the following structure?

topjm [15]

Answer:

You are not showing the question, but I believe the answer is cis-3,4-dimethyl-3-hexene.

Explanation:

since the substituents are on same side, it call cis. Followed by the name.

5 0

3 years ago

The chemical potassium sulfate, commonly known as potash of sulfur, is used in fertilizers. This chemical provides both potassiu

marin [14]

Answer: $H_2SO_4(aq)+2KOH(aq)\rightarrow K_2SO_4(aq)+2H_2O(l)$

Explanation:

Neutralization is a chemical reaction in which acid and base combine to form salt and water. Acids donate $H^+$ ions and bases donate $OH^-$ ions in water which combine to form water molecules.

The balanced molecular equation is ;

$H_2SO_4(aq)+2KOH(aq)\rightarrow K_2SO_4(aq)+2H_2O(l)$

8 0

3 years ago

How many molecules would there be in 10.5 L of carbon dioxide at 40.0 C and 252 kPa

kakasveta [241]

Answer:

6.14×10²³ molecules

Explanation:

Data obtained from the question include:

Volume (V) = 10.5L

Temperature (T) = 40°C

Pressure (P) = 252 kPa

Next, we shall determine the number of mole of CO2 present.

This can be obtained by using the ideal gas equation:

PV = nRT

Volume (V) = 10.5L

Temperature (T) = 40°C = 40°C + 273 = 313K

Pressure (P) = 252 kPa

Gas constant (R) = 8.31 KPa.L/Kmol

Number of mole (n) =.?

PV = nRT

252 x 10.5 = n x 8.31 x 313

Divide both side by 8.31 x 313

n = (252 x 10.5) /(8.31 x 313)

n = 1.02 mole

Therefore, 1.02 mol of CO2 is present.

Now, we can obtain the number of molecules of CO2 present as follow:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02×10²³ molecules.

This means that 1 mole of CO2 also contains 6.02×10²³ molecules.

Now, if 1 mole of CO2 contains 6.02×10²³ molecules,

Then 1.02 mole will contain = 1.02 x 6.02×10²³ = 6.14×10²³ molecules.

Therefore, 6.14×10²³ molecules of CO2 is present.

8 0

4 years ago

In the lab you react 2.0 g of Na2CO3 with enough CaCl2. According to the reaction Na2CO3 + CaCl2 -> CaCO3 + 2NaCl How much Ca

vlada-n [284]

Answer:

1.89 g CaCO₃

Explanation:

You will have to use stoichiometry for this question. First, look at the chemical equation.

Na₂CO₃ + CaCl₂ ==> 2 NaCl + CaCO₃

From the above equation, you can see that for one mole of Na₂CO₃, you will produce one mole of CaCO₃. This means that however many moles of Na₂CO₃ you have in the beginning, you will have the same amount of moles of CaCO₃, theoretically speaking.

So, convert grams to moles. You should get 0.0189 mol Na₂CO₃. This means that you will get 0.0189 mol CaCO₃. I'm not sure what units you want the answer in, but I'm going to give it in grams. Convert moles to grams. Your answer should be 1.89 g.

3 0

4 years ago

9. Given the following reaction:CO (g) + 2 H2(g) CH3OH (g)In an experiment, 0.45 mol of CO and 0.57 mol of H2 were placed in a 1

WITCHER [35]

Answer:

$Keq=11.5$