Helppp I really need this question answered
1 answer:
Answer:
32.5 units²
Step-by-step explanation:
We can find the area by dividing the figure into two shapes. If we solve for the area of a square and a triangle, we can add them together.
First, we can solve for the area of the 5x5 square. To find the area, we can multiply the two dimensions.
5 · 5 = 25 units²
Next, we can find the area of the triangle. It has an equal height to the square, so the height of the triangle is 5 units. The width isn't specified. Instead, we are shown that the width of both the square and the triangle equals 8 units. If we subtract the width of the square from the total, we can find the width of the triangle, too.
8 - 5 = 3
So, the height and the width of the triangle are 5x3. To find the area we can multiply these together, and then divide the product by two.
5 · 3 = 15
= 7.5
The area of the triangle is 7.5 units².
Finally, we can add the area of the triangle and the square together.
25 + 7.5 = 32.5
The area of the figure, then, is 32.5 units².
The answer is the last option.
I hope this helps ^^
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Since you need the vertex, and knowing the vertex will tell you the axis of symmetry, it is convenient to put the equation in vertex form.
.. -x^2 -4x +1
.. = -(x^2 +4x) +1
.. = -(x^2 +4x +(4/2)^2) +1 -(-(4/2)^2) . . . . complete the square
.. = -(x +2)^2 +5
The vertex is (-2, 5).
The axis of symmetry is x = -2.
.. -x^2 -4x +1
.. = -(x^2 +4x) +1
.. = -(x^2 +4x +(4/2)^2) +1 -(-(4/2)^2) . . . . complete the square
.. = -(x +2)^2 +5
The vertex is (-2, 5).
The axis of symmetry is x = -2.