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Vesna [10]
3 years ago
9

A quantity with an initial value of 8100 decays continuously at a rate of 0.95% per year. What is the value of the quantity afte

r 96 months, to the nearest hundredth?
Mathematics
2 answers:
aliina [53]3 years ago
7 0

Answer:

7507.21

Step-by-step explanation:

mafiozo [28]3 years ago
6 0

Answer:

20163.299

Step-by-step explanation:

Initial value = 8100

Rate r = 0.95% = 0.0095

t = 96 month

Therefore, Value of the quantity after 39 decades = Initial value*e^(rt)

= 8100*e^(0.0095*96)

= 8100*e^(0.912)

= 8100*2.48929615041

= 20163.298818321

= 20163.299

So, the value of the quantity after 96 months is 20163.299

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Juliette [100K]

Answer:

Option D: 12\frac{1}{2} is the correct answer.

Step-by-step explanation:

Given that:

3/4 inches on map are equal to 7\frac{1}{2} miles

We will find the unit rate in term of inches.

\frac{3}{4}\ inches = 7\frac{1}{2}\\\\Unit\ rate = \frac{15}{2}*\frac{4}{3}\ miles\\\\Unit\ rate = 10\ miles\ per\ inch

Total distance covered by Bonnie according to map;

Total distance = \frac{1}{2}+\frac{3}{4} = \frac{2+3}{4}

Total distance = \frac{5}{4}\ miles

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Hence,

Option D: 12\frac{1}{2} is the correct answer.

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Answer:

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Step-by-step explanation:

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rusak2 [61]

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