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Margarita [4]
2 years ago
7

Simplify 8/-3 divided -4/9

Mathematics
1 answer:
alexdok [17]2 years ago
8 0

Answer:

6

Step-by-step explanation:

You might be interested in
Can someone put a website to help me understand this?
Alenkinab [10]

Answer:

67

Step-by-step explanation:

Since the diagonals in a rectangle are congruent, AC=BD and

7x+18=10x-3

We need to separate x -- to do that, we can first subtract 7x from both sides, resulting in

18=3x-3

Next, add 3 to both sides to get

21=3x

Divide both sides by 3 to get

x=7

Then, we just plug x into 10x-3 to get BD = 7*10-3 = 67

7 0
2 years ago
If an area can be washed at a rate of 3,600 cm2/minute, how many square inches can be washed per hour? Enter your answer with th
r-ruslan [8.4K]

Answer:

276923 square inches

Step-by-step explanation:

I probably got it wrong to be honest

4 0
3 years ago
George plans to cover his circular pool for the upcoming winter season. The pool has a diameter of 20 feet and the cover extends
Verizon [17]

Answer:

Area of Pool cover: 110.25π

Length of rope: 21π

Step-by-step explanation:

To find the area of a circle the formula is πr^2.

1. take 10.5, which is half of the diameter and multiply it by itself then multiply by pi(π). Answer is 110.25π

To find the length of the rope(circumference) the formula is 2πr.

1. Take r, which we established as 10.5 then multiply it by 2, which is 21. Then multiply by π. Answer is 21π

____________________________________________________________

If ur teacher wants you to use 3.14 as pi then these are your answers:

Area of Pool cover: 346.185, round up to 346.19 if needed

Length of rope: 65.94

8 0
3 years ago
Factor each completely
avanturin [10]
K^2-5k-50
(k-10)(k+5)

This is because k*k=k^2 (your first term), 5k-10k=-5k (your second term) and -10*5=-50 (your last term).

Distribute to check.
3 0
2 years ago
Use polar coordinates to find the volume of the given solid. bounded by the paraboloid z = 5 + 2x2 + 2y2 and the plane z = 11 in
podryga [215]
Using cylindrical coordinates,

\displaystyle\int_{x=0}^{x=\sqrt3}\int_{y=0}^{y=\sqrt{3-x^2}}\int_{z=5+2x^2+2y^2}^{z=11}\mathrm dz\,\mathrm dy\,\mathrm dx
\displaystyle=\int_{\theta=0}^{\theta=\pi/2}\int_{r=0}^{r=\sqrt3}\int_{z=5+2r^2}^{z=11}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\displaystyle\frac\pi2\int_{r=0}^{r=\sqrt3}r(11-(5+2r^2))\,\mathrm dr
=\displaystyle\pi\int_{r=0}^{r=\sqrt3}(3r-r^3)\,\mathrm dr
=\dfrac{9\pi}4
3 0
3 years ago
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