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2 years ago

Nine is 4 percent of what number

Mathematics

2 answers:

ale4655 [162]2 years ago

8 0

Answer:

225

Step-by-step explanation:

Is means equals and of means multiply

9 = 4% * W

Change to decimal form

9 = .04 * W

Divide each side by .04

9/.04 = .04W/.04

225 = W

Katarina [22]2 years ago

5 0

Answer:

225

Step-by-step explanation:

We can model this question with:

9 = 0.04x

x represents "what number."

0.04x = 9.

Divide 0.04 from both sides

0.04x ÷ 0.04 = 9 ÷ 0.04

9 ÷ 0.04 = 225.

Therefore, 9 is 4% of 225.

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Please help asap !!!!!

gayaneshka [121]

Answer:

Part A

The table is filled in based on given data.

Total = 160
Snake = 160*0.4 = 64
No snake = 160 - 64 = 96
Snake and lizard = 64*0.25 = 16
Snake no lizard = 64 - 16 = 48
No snake lizard = 96*0.75 = 72
No snake no lizard = 96 - 72 = 24

<em>See attached</em>

Part B

88 out of 160
88/160*100% = 55%

Part C

16 out of 160
16/160*100% = 10%

8 0

2 years ago

How many hours would someone who earns $6.25 per hour have to work to earn $225.65?

AURORKA [14]

6.25x = 225.65
x = 225.65 / 6.25
x = 36.104....so u would basically have to work 37 hrs

3 0

2 years ago

Read 2 more answers

What is the factored form of 11x-x^2=0

Aleks [24]

Answer: $x(11-x)=0$

Step-by-step explanation:

Given the quadratic equation $11x-x^2=0$ , you need to factor it.

In order to find the form asked of the given equation, you need to factor out the common factor of the terms.

You can observe that the common factor of the terms of the equation is: $x$

Now, knowing this, you must factor out $x$ . Then you get the following form:

$x(11-x)=0$

Therefore, the factored fom of the equation $11x-x^2=0$ is:

$x(11-x)=0$

3 0

3 years ago

A research study investigated differences between male and female students. Based on the study results, we can assume the popula

oksian1 [2.3K]

Answer: 0.0548

Step-by-step explanation:

Given, A research study investigated differences between male and female students. Based on the study results, we can assume the population mean and standard deviation for the GPA of male students are µ = 3.5 and σ = 0.05.

Let $\overline{X}$ represents the sample mean GPA for each student.

Then, the probability that the random sample of 100 male students has a mean GPA greater than 3.42:

$P(\overline{X}>3.42)=P(\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}>\dfrac{3.42-3.5}{\dfrac{0.5}{\sqrt{100}}})\\\\=P(Z>\dfrac{-0.08}{\dfrac{0.5}{10}})\ \ \ [Z=\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}]\\\\=P(Z>1.6)\\\\=1-P(Z$

hence, the required probability is 0.0548.

6 0

3 years ago

X is less than or equal to 9 and greater than or equal to 5

topjm [15]

5≤x≤9 it can also be reversed as 9≥x≥5 which is the same thing

3 0

3 years ago

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