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melamori03 [73]
3 years ago
10

The temperature in Mr. Garcia's fish tabk is 7°C at 1pm Ms. Pennington places an icepack in the tank , causing the temperature o

f the water to drop at a rate of rate of 3 degrees per hour for the nest 5 hours. What is the temperature at 6pm?
Mathematics
1 answer:
tatyana61 [14]3 years ago
5 0

Answer:

First, Multiply 5 by 3 to get how much the temperature decreased.

5*3=15

Then, add 7 to 15 to get the total amount how much the temperature decreased.

15+7=22

The answer to your question is 22.



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Use the given minimum and maximum data​ entries, and the number of​ classes, to find the class​ width, the lower class​ limits,
Gennadij [26K]

Using proportions and the information given, it is found that:

  • The class width is of 14.375.
  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

-------------------------

  • Minimum value is 19.
  • Maximum value is of 134.
  • There are 8 classes.
  • The classes are all of equal width, thus the width is of:

W = \frac{134 - 19}{8} = 14.375

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

6 0
3 years ago
3. Find the MEDIAN of the following data set: 82, 99, 76, 91, 89, 95.
GaryK [48]

Answer:

76 and 91

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the range of all the multiples of 3 between 10 and 20
Len [333]

List the multiples of 3:

3, 6, 9, 12, 15, 18,21

The ones between 10 and 20 are:

12, 15, 18

The range is the difference between the highest and lowest numbers.

Range = 18 - 12 = 6

3 0
3 years ago
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The weight of an organ in adult males has a​ bell-shaped distribution with a mean of 320 grams and a standard deviation of 50 gr
ch4aika [34]

Answer:

a) 68% of organs will be between 270 and 370 grams

b) 95%

c) 5%

d) 97.35%

Step-by-step explanation:

Empirical rule states that

1 standard deviation means a 68% of total area under the normal distribution. On one side is half = 34%.

2 standard deviations means a 95% of total area under the normal distribution. On one side is half = 47.5%.

3 standard deviation means a 99.7% of total area under the normal distribution. On one side is half = 49.85%.

a) Since 1 standard deviation means a 68% of total area under the normal distribution, we have

320 + 50 = 370

320 – 50 = 270

68% of organs will be between 270 and 370 grams

b) Calculate the difference between mean and the percentage of weight of an organ in the problem:

420 – 320 = 100

320 – 220 = 100

Since standard deviation is 50 grams, there is a difference of 2 standard deviations for both sides. According to the rule 95% of the organs are between 200 and 420 grams.  

c) Since 95% of the organs are between 200 and 420 grams, 5% weighs less than 220 grams or more than 420 grams.

d) Calculate the difference between mean and the percentage of weight of an organ in the problem:

420 – 320 = 100

320 – 170 = 150

Since standard deviation is 50 grams, there is a difference of 2 standard deviations for the right side and 2 standard deviations for the left side. According to the rule for 2 standard deviations on one side there is 47.5% and for 3 standard deviations on one side there is 49.85%. so percentage of organs weighs between 170 grams and 420 grams is 47.5% + 49.85% = 97.35%.

8 0
3 years ago
The mayor is interested in finding a 95% confidence interval for the mean number of pounds of trash per person per week that is
Hatshy [7]

Answer:

A. <u>Normal</u>

B. <u>30.1</u>, <u>32.9</u>

C. <u>95</u>, <u>5</u>

Step-by-step explanation:

A. The sampling distribution follows a <u>normal</u> distribution

Given that the sample size is large, we have that the sample distribution follows a normal distribution according to the central limit theorem

B. The 95% confidence interval is given as follows;

CI=\bar{x}\pm z \times \dfrac{s}{\sqrt{n}}

The number of residents in the study, n = 120 residents

The sample mean, \overline x = 31.5 pounds

The standard deviation, s = 7.8 pounds

The z-value for 95% confidence level, z = 1.96

Therefore, we get;

C.I. = 31.5 ± 1.96 × 7.8/√(120)

The 95% C.I. ≈ 30.1 ≤ \overline x ≤ 32.9

Therefore, we have that with 95% confidence, the population mean number of pounds per person per week is between <u>30.1</u> and <u>32.9</u>

C. Therefore, according to the central limit theorem, about <u>95</u> percent of the groups of 120 will contain the true population mean number of pounds of trash generated per person per week and about <u>5</u> percent will not contain the true population mean number of pounds of trash generated per person per week.

8 0
3 years ago
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