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Daniel [21]
3 years ago
6

ramesh can complete a piece of work in 10 days he worked for 4 days and left. if dinesh complete the remaining part of the work

,how much work was done by dinesh​
Mathematics
1 answer:
kirill [66]3 years ago
8 0

Answer:

100% of the work was done by him

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Factor (16a2 - 49) completely
riadik2000 [5.3K]

Answer:

(4a+7)(4a-7)

Step-by-step explanation:

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3 years ago
Can the distributive property be used to rewrite
Harman [31]

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I think No

Step-by-step explanation:

6 0
4 years ago
BELP ME WITH THIS PLZ!!!!!!
kati45 [8]

Answer:

The entire area of the sailboat is 60cm²

Step-by-step explanation:

You can find the area of this shape by breaking it down into simpler shapes and adding up their individual areas.

In this case, the areas we'll use are the rectangle at the bottom, and the pair of triangles at the top.

Because the two triangles can be put together to form a single triangle, we don't need to measure them independently.  We can simply take the total length of their bases, multiply it by their height, and divide by two.  This follows the rule that the area of a triangle is equal to the area of the square that contains it divided by two.

(2cm + 3cm) × 6cm

= 5cm × 6cm

= 30cm²

The rectangle's area is of course equal to its width times its height, so we can say:

2.5cm × 12cm

= 30cm²

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3 0
3 years ago
The heat developed in an electric wire varies jointly as the wires resistance, the time the current flows, & the square of t
never [62]

Answer:

4 ohms

Step-by-step explanation:

The question is "In two minutes a current of 5 amps develops 1,200 heat units in a wire of 8 ohms resistance. What resistance does a similar wire have, which develops 6,000 heat units with a current of 10 amps in 5 minutes?"

Current, I₁ = 5 A

Heat, Q₁ = 1200 units

Resistance, R₁ = 8 ohms

Time, t₁ = 2 min = 120 s

New heat, Q₂ = 6000 units

Current, I₂ = 10 A

New time, t₂ = 5 min = 300 s

We need to find the new resistance.

Heat developed is given by :

Q=I^2Rt

\dfrac{Q_1}{I_1^2R_1t_1}=\dfrac{Q_2}{I_2^2R_2t_2}\\\\R_2=\dfrac{Q_2\times I_1^2R_1t_1}{Q_1I_2^2t_2}\\\\R_2=\dfrac{6000\times 5^2\times 8\times 120}{1200\times 10^2\times 300}\\\\=4\ \Omega

So, the new resistance is 4 ohms.

5 0
3 years ago
Help me with this problem
vova2212 [387]

Answer:

The answer is 180 - 65

Step-by-step explanation:

We got 180, because that is the number of degree's in a line

so 180 - 65 is 115 degrees, that's your answer :)

7 0
3 years ago
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