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madam [21]
3 years ago
13

What is the inverse of y = 16x^2 + 1

Mathematics
1 answer:
tankabanditka [31]3 years ago
4 0
X = 16y^2 + 1
x - 1 = 16y^2
(x - 1)/16 = y^ 2
( (x-1) / 16 ) ^1/2 = y
( (x-1) ^ 1/2 ) / 4 = y
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Answer:

2(b+1+b)= 18

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2 years ago
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Lemur [1.5K]

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