I got 0.03cm^3 or 3 cm cubed hope i helped
Use the pythagorean theorem to solve this: a^2 + b^2 = c^2.
You already have a and b which are 3 and 4. Square them up and you will get 9 + 16 = c^2.
Add.
25 = c^2
Lastly, square root both sides.
5 = c
The length of AB is 5.
Answer:
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Step-by-step explanation:
y = (x^2 - 3)^sinx
ln y = ln (x^2 - 3)^sinx
ln y = sin x * ln (x^2 - 3)
1/y * dy/dx = sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x
1/y dy/dx = 2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)
dy/dx = [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
