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KonstantinChe [14]
3 years ago
6

1. How are atoms held together? What is the attraction between?

Chemistry
2 answers:
barxatty [35]3 years ago
3 0

Answer:

the atom is held together by the electrostatic attraction between the positively charged nucleus and the negatively charged electrons surrounding it, the stability within chemical bonds is also due to electrostatic attractions.

Explanation:

Irina-Kira [14]3 years ago
3 0

Answer:

Some type of bond (example: hydrogen bonds between water)

Polarity can also hold atoms together

hope this Helped!

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8. A student passes a magnet over 10 g of a powder. Four grams of the powder stick to the magnet, while 6 g do not. Which of the
vladimir1956 [14]

Answer:

mixture

Explanation:

The properties of the components of substance are different. One component has magnetic properties, another does not. So, we have at least 2 individual substances that were mixed together. So, we have a mixture.

7 0
3 years ago
Read 2 more answers
Strontium oxide + ? =<br>stronium chloride​
White raven [17]

Answer:

strontium oxide + hydrochloric acid (HCL) =   strontium chloride​

8 0
3 years ago
If 10.0 liters of oxygen at STP are heated to 785.15 °K, what will be the new volume of gas if the pressure is also increased to
Ugo [173]

Answer: The new volume of gas is 28.5 L

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 1.00 atm (at STP)

P_2 = final pressure of gas = 102.6 kPa = 1.01 atm    (1 kPa= 0.0098 atm)

V_1 = initial volume of gas = 10.0 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 273.15K  (STP)

T_2 = final temperature of gas = 785.15K

Now put all the given values in the above equation, we get:

\frac{1.00\times 10.0}{273.15}=\frac{1.01\times V_2}{785.15}

V_2=28.5L

The new volume of gas is 28.5 L

8 0
3 years ago
...............................................<br> .
Sergio [31]

Answer:

yuh

Explanation:

5 0
3 years ago
When the concentrations of CH 3 Br and NaOH are both 0.100 M, the rate of the reaction is 0.0030 M/s. What is the rate of the re
mash [69]

Answer : The rate of the reaction if the concentration of CH_3Br is doubled is, 0.006 M/s

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The balanced equations will be:

CH_3Br+NaOH\rightarrow CH_3OH+NaBr

In this reaction, CH_3Br and NaOH are the reactants.

The rate law expression for the reaction is:

\text{Rate}=k[CH_3Br][NaOH]

As we are given that:

[CH_3Br] = concentration of CH_3Br = 0.100 M

[NaOH] = concentration of NaOH = 0.100 M

Rate = 0.0030 M/s

Now put all the given values in the above expression, we get:

0.0030M/s=k\times (0.100M)\times (0.100M)

k=0.3M^{-1}s^{-1}

Now we have to calculate the rate of the reaction if the concentration of CH_3Br is doubled.

\text{Rate}=k[CH_3Br][NaOH]

\text{Rate}=(0.3M^{-1}s^{-1})\times (2\times 0.100M)\times (0.100M)

\text{Rate}=0.006M/s

Thus, the rate of the reaction if the concentration of CH_3Br is doubled is, 0.006 M/s

3 0
4 years ago
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