The quantities you have to know are the molar masses and the molecular stoichiometric ratios. The solution for this problem is as follows:
Mass Percent of Iodine = (Mass of Iodine/Mass of NaBr and KI)*100
Mass of NaBr = 1 mol NaBr * 102.89 g/mol = 102.89 g
Mass of KI = 0.3 mol KI * 166 g/mol = 49.8 g
Mass of KI = 0.3 mol KI * 1 mol I/1mol KI * 1 mol I₂/2 mol I * 253.81 g/mol = 38.07 g
Mass %I₂ = 38.07/(102.89+49.8) * 100 = <em>24.9%</em>
The S and P blocks are known as orbitals
We want to write the nuclear equation for the beta decay of Aluminium-25.
The equation is:
First, as you may know, in a beta decay the number of protons is increased by one. Aluminium has 13 of them, so after the decay, we will have 14 protons.
This means that the aluminium will transform into silicon, then the nuclear equation is just:
Where the:
Is an electron, which is the emitted particle in the beta decay.
If you want to learn more, you can read:
brainly.com/question/4184205
Answer:
Carbon
Explanation:
The non metal in the same group as Pb is carbon or C .
I hope this helps you.
Explanation:
mass = no. of moles x molar mass (Mr)
i- mass = 10.2 mol x 30 g/mol
= 306 g
ii- mass of potassium hydroxide = 0.0146 mol x 56g/mol
= 0.8176g
mass of calcium hydroxide= 0.0146mol x 74 g/mol
= 1.0804g