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Neporo4naja [7]
3 years ago
12

Braden logged 3 2/3 hours last week in his reading journal and 2 3/6 hours last week how many fewer hours did Brayden log in his

reading journal this week then last week​
Mathematics
1 answer:
lubasha [3.4K]3 years ago
5 0

Answer:

1 1/6

Step-by-step explanation:

im guessing you need this fast so i wont explain it

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S = 2B + L. What do S, B, and L stand for?
notsponge [240]
Hi Jordyn! I think S is segment, B is base, and L is length. I hope this helped!
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The sum of three consecutive odd numbers is 51. What is the second number in this sequence?
Margarita [4]
Well I would say it is 25+25+1=51
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3 years ago
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Simplify the sum.<br> (4u3 + 4u2 + 2) + (6u3 – 2u + 8)
Elan Coil [88]

Answer:

10u^{3}+4u^{2}-2u+10 or 2(5u^{3}+2u^{2}-u+5)

Step-by-step explanation:

we have

(4u^{3}+4u^{2} +2)+(6u^{3}-2u+8)

step 1

Group terms that contain the same variable

(4u^{3}+6u^{3})+(4u^{2})+(-2u)+(2+8)

step 2

Combine like terms

(10u^{3})+(4u^{2})+(-2u)+(10)

step 3

Eliminate parenthesis

10u^{3}+4u^{2}-2u+10

step 4

Factor the number 2

2(5u^{3}+2u^{2}-u+5)

8 0
3 years ago
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Help Please, will give brainiest.
hichkok12 [17]

Answer:

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Step-by-step explanation:

6 0
3 years ago
a statistics professor finds that when he schedules an office hour at the 10:30a, time slot, an average of three students arrive
Veseljchak [2.6K]

Answer:

The probability that in a randomly selected office hour in the 10:30 am time slot exactly two students will arrive is 0.2241.

Step-by-step explanation:

Let <em>X</em> = number of students arriving at the 10:30 AM time slot.

The average number of students arriving at the 10:30 AM time slot is, <em>λ</em> = 3.

A random variable representing the occurrence of events in a fixed interval of time is known as Poisson random variables. For example, the number of customers visiting the bank in an hour or the number of typographical error is a book every 10 pages.

The random variable <em>X</em> is also a Poisson random variable because it represents the fixed number of students arriving at the 10:30 AM time slot.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 3.

The probability mass function of <em>X</em> is given by:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,3...,\ \lambda>0

Compute the probability of <em>X</em> = 2 as follows:

P(X=2)=\frac{e^{-3}3^{2}}{2!}=\frac{0.0498\times 9}{2}=0.2241

Thus, the probability that in a randomly selected office hour in the 10:30 am time slot exactly two students will arrive is 0.2241.

6 0
3 years ago
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