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3 years ago

The LCD for 17 and 1/2 is 07 08 15 56

Mathematics

1 answer:

alexira [117]3 years ago

3 0

Answer:

its 2

Step-by-step explanation:

Rewriting input as fractions if necessary:

17/1, 1/2

For the denominators (1, 2) the least common multiple (LCM) is 2.

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What is the solution to this equation?

vampirchik [111]

Steps to solve:

x - 5 = 2

~Add 5 to both sides

x = 7

Best of Luck!

5 0

2 years ago

Write the equation of a line that is perpendicular to y=3x-2 that passes trough the point (-9,5)

ElenaW [278]

$\huge\boxed{y-5&=-\frac{1}{3}(x+9)}$

First, we'll find the slope of the new line. The first line has a slope of $3$ . Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by $-1$ ) to get $-\frac{1}{3}$ for the new slope.

Then, we'll use the point-slope form to make the new equation, where $m$ is the slope and $(x_1,y_1)$ is a point on the line:

$\begin{aligned}y-y_1&=m(x-x_1)\\y-5&=-\frac{1}{3}(x-(-9))\\y-5&=-\frac{1}{3}(x+9)\end{aligned}$

3 0

1 year ago

Read 2 more answers

Solve the following proportion for V. 3/11=v/6 Round your answer to the nearest tenth.

GalinKa [24]

Answer:

I think the answer would be 0.2

Step-by-step explanation:

6 0

3 years ago

Is the sum of the areas of two smaller squares equal to the area of a large square if the side lengths of the squares are 8 feet

Ivanshal [37]

No, the sum of the areas of two smaller squares is not equal to the

area of a large square

Step-by-step explanation:

To solve this problem let us do these steps

1. Find the area of the larger square

2. Find the area of the two smaller squares

3. Add the areas of the two smaller squares

4. Compare between the sum of the areas of the 2 smaller squares

and the area of the larger square

The area of a square is s²

The length of the side of the larger square is 8 feet

∵ s = 8 feet

∴ Area of the larger square = (8)² = 64 feet²

The lengths of the sides of the smaller squares are 5 feet and 3 feet

∵ s = 5 feet

∴ The area of one of the smaller square = (5)² = 25 feet²

∵ s = 3 feet

∴ The area of the other smaller square = (3)² = 9 feet²

The sum of the areas of the two smaller squares = 25 + 9 = 34 feet²

∵ The area of the larger square is 64 feet²

∵ The sum of the areas of the two smaller squares is 34 feet²

∵ 64 ≠ 34

∴ The sum of the areas of two smaller squares is not equal to the

area of a large square

<em>No, the sum of the areas of two smaller squares is not equal to the</em>

<em>area of a large square</em>

Learn more:

You can learn more about the areas of figures in brainly.com/question/3306327

#LearnwithBrainly

4 0

3 years ago

our buses carrying 140 high school students arrive to Montreal. The buses carry, respectively, 31, 43, 27, and 39 students. One

Vinvika [58]

Answer:

V(X)= 39.10

V(Y)= 40

Step-by-step explanation:

Given that

Total number of student = 140

Bus A - 31

Bus B- 43

Bus C- 27

Bus D- 39

The probability that a student was on the bus is proportional to the number of student. Eg 31/140 in bus A, 43/140 on bus B, ...

E(X) = (31*31/140) + (43*43/140) + (27*27/140) + (39*39/140)

= 35.5

$Var(X) =(31-35.5)^2 \times \dfrac{31}{140}+(43-35.5)^2 \times \dfrac{43}{140}+(39-35.5)^2 \times \dfrac{39}{140}+(27-35.5)^2 \times \dfrac{27}{140}$

V(X)= 39.10

The bus driver have 1/4 probability on being on any of the buses.

E(Y) = 140/4 = 35

$Var(Y)=\dfrac{(35-31)^2+(35-43)^2+(35-27)^2+(35-39)^2}{4}$

V(Y)= 40

7 0

3 years ago