The probability of having a 17 is the number of ways of having 17 divided by the number of different possible outcomes.

Ways of having 17:

Die 1 Die 2 Die 3 sum
6    6    5 6+6+5 = 17
6    5    6     6+5+6 = 17
5    6    6     5+6+6 = 17

Those are the only 3 possibilities of having 17 (you can only loose 1 point).

The total number of outcomes are 6*6*6 = 216

So the chances (probability) to win is 3 / 216 = 1/72 = 0.0139

8 0

3 years ago

Use the following for long division x^2+3x+1sqrt 3x^4+7x^3+2x^2+13x+5

goldenfox [79]

In plain text, it is appropriate to express the division using a division bar (/) and parentheses around the numerator and denominator:
(3x^4 +7x^3 +2x^2 +13x +5)/(x^2 +3x +1)

It is best to reserve the square root symbol (√) for an actual square root.

Your quotient is
3x^2 -2x +5

8 0

3 years ago