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IgorLugansk [536]
4 years ago
10

How do you do 4x - 9 = 6x - 13? what do you subtract from both sides?

Mathematics
2 answers:
ohaa [14]4 years ago
8 0
To start, you need to subtract 4x from both sides, that way, x is one one sid of the equation.

aleksley [76]4 years ago
8 0
Simple....

you have: 4x-9=6x-13

-->>Isolate the variable..(x)

4x-9=6x-13
-4x   -4x

-9=2x-13
+13    +13

4=2x

2=x

Plug it in..to make sure it is correct.....

4(2)-9=6(2)-13

8-9=12-13

-1=-1

Correct.

Thus, your answer.


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First make sure your numbers are all on one side leaving zero on the other side:
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The next step is the tricky part to explain. So look on the first number and the third number in the formula. The first number is 1z². What multiples equal 1? The only multiples would be one times one (1 x 1). So below z² write one over one like this:
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\frac{1}{1}
But remember this is 1 x 1 and not actually division. For the + 11, think of all the multiples that equal positive 11. It can be 1 x 11 or -1 x -11 so put the first option in fraction form first to test. It doesn't matter which is on top or bottom.
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Now you need to cross multiply here. 1 x 11 and 1 x 1. That will give you two positive numbers 1 and 11. In order to get your middle number from step 1 you need to add these two numbers and see if you will get -12. As you can see 11 + 1 doesn't equal -12 so now we need to use our second option -1 x -11. Our paper should now be changed to this:
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Now you just need to rearrange your fractions here. you can replace your 1 over one to z over z since z x z still equals your problem's z²:
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Finally solve for z. Separate parentheses to two separate equations like this:
z - 11 = 0 and z - 1 = 0
z = 11 and z = 1
That should be your answer. Sorry if it still doesn't make sense still.
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