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3 years ago

Please help with math

Mathematics

1 answer:

irakobra [83]3 years ago

8 0

Answer:

5 and 6

Step-by-step explanation:

You have to find two numbers (in the chart) that have a difference of 3/8.

This is just one possiblity, there are other correct answers.

There is size 5 and 6. 9 and 4/8-9 and 1/8=3/8.

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Hello people ~<br>factorise↷<br> x^2 + 4x –21

EleoNora [17]

Let's see

$\\ \rm\rightarrowtail x^2+4x-21$

$\\ \rm\rightarrowtail x^2+7x-3x-21$

$\\ \rm\rightarrowtail x(x+7)-3(x+7)$

$\\ \rm\rightarrowtail (x-3)(x+7)$

8 0

2 years ago

Measures of Center

GalinKa [24]

Answer:

1. mean

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Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

James defines a line segment as "a portion of a line." His statement is not precise enough because he should specify that

vekshin1

Answer: D. the segment has two endpoints.

Step-by-step explanation:

A line segment refers to a part of a line which is bounded by two distinct end points. The line segment is part of the line which helps in the connection of two points that are considered to be the endpoints.

A line segment is the distance between the two points and which one measure.

They can be used to form a side of a polygon because they have a defined length.

8 0

3 years ago

On Tuesday Jack bought four boxes. On Wednesday half of all the boxes that he had were destroyed. Write an expression for how ma

Kipish [7]

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5 0

3 years ago

GCSE 995381

nikdorinn [45]

Answer:

$2.9 cm^2$

Step-by-step explanation:

Given,

Angle of sector = 30°

Radius of circle, r = 8 cm

Area of the shaded region, A =?

The diagram is attached below.

Now,

Area of shaded region = Area of sector - Area of triangle

Area of triangle = $\frac{1}{2}\times base \times height$

We know that,

$\sin \theta = \dfrac{P}{H}$

$\sin 30^\circ= \dfrac{P}{8}$

$P = \dfrac{8}{2}$

$P = 4\ cm$

And

$\cos \theta =\dfrac{B}{H}$

$\cos 30^\circ = \dfrac{B}{8}$

$B = \dfrac{8\times \sqrt{3}}{2}$

$B = 4\sqrt 3$

Area of sector = $\dfrac{\theta}{360^\circ}\times \pi r^2$

Area of sector = $\dfrac{30^\circ}{360^\circ}\times \pi \times 8^2$

= 16.75 cm^2

Area of triangle = $\dfrac{1}{2} \times 4\sqrt 3 \times 4$

= 13.85 cm^2

Area of shaded region = 16.75 - 13.85

= $2.9 cm^2$

7 0

3 years ago

Please help with math ​

Please help with math