Answer:
lateral surface area = 48 inches²
Step-by-step explanation:
The picture below is the square base pyramid you are referring. The lateral area is adding the area of the 4 triangles in the pyramid.
area of a triangle = 1/2 × b × h
The slant height of the triangle is gotten using Pythagoras theorem
lateral surface area = 4 × (1/2 × 3 × 8)
lateral surface area = 4 × 24/2
lateral surface area = 4 × 12
lateral surface area = 48 inches²
My best choice is A. -76. I might be wrong! Best of luck. :-)
<em>Greetings from Brasil...</em>
In function F(X) = X², if we replace X with X + 4 we will have exactly function G(X) = (X + 4)²
So, just replace X for X + 4..... This will be responsible for translating 4 units to the left, because:
F(X) = X²
F(X + 4) = (X + 4)²
F(X + 4) ⇔ F(X + k) <em> see below</em>
We know that the translations are established as follows:
→ Horizontal
F(X + k) ⇒ k units to the left
F(X - k) ⇒ k units to the right
<em>see more:</em>
<em>brainly.com/question/17163323</em>
Answer:
x=3 and y=2
Step-by-step explanation:
The pythagorean triples are generated by two integrers x and y that can be found by solving the following system of equations:

Solve the system of equations, and we get that the solution is x=3 and y=2.
Therefore, the combination of integrers that ca be used to generate the pythagorea triple are: x=3 and y=2
Carlos made the mistake that he did not combine like terms (3 x and 2 x) properly and did not use addition property of equality.
<u>Step-by-step explanation:</u>
Carlos did the work as 3 x + 2 x - 6 = 24
We need to find his mistake that he made in above given.
Here, he did not add the like terms (3 x and 2 x)
3 x + 2 x = 5 x
Therefore, his work should be
5 x - 6 = 24
Also, he did not use addition property of equality. It means the equation remains same even though the same number gets added on both sides. It would be
5 x - 6 = 24
+ 6 = + 6
-----------------------
5 x = 30
Dividing 30 by 5, we get answer as '6'. Hence,
= 6
So, stated the above two are the mistakes found in carlos work.