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enot [183]
3 years ago
11

Find the length of JL 15 None of the other answers are correct 12 3

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
3 0

Answer:

D: 12

Step-by-step explanation:

The entire segment KI is composed of the segments KJ and JI. So:

KI=KJ+JI

We know that KI is 15.

KJ is (2x-15) and JI is (2x-6). Substitute:

15=(2x-15)+(2x-6)

Solve for x. Combine like terms:

15=4x-21

Add 21 to both sides:

4x=36

Hence, the value of x is:

x=9

We know that JI is 2x-6.

We will substitute 9 for x to find JI. So:

JI=2(9)-6=18-6=12

Hence, our answer is D.

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Write 14/√2 + √50 in the form b√2 where b is an integer.
kifflom [539]

Answer:

12 \sqrt{2}

Step-by-step explanation:

Taking the terms one at a time,

\frac{14}{ \sqrt{2} }  \\   \frac{14 *  \sqrt{2} }{ \sqrt{2} *  \sqrt{2}  }  \\   \frac{14  \sqrt{2} }{2}  \\  7 \sqrt{2}

\sqrt{50} \\  \sqrt{25 * 2} \\  \sqrt{25}*  \sqrt{2}    \\ 5 *  \sqrt{2}   \\ 5 \sqrt{2}

Adding the terms, you have;

7 \sqrt{2} + 5 \sqrt{2} =(7 + 5) \sqrt{2} = 12 \sqrt{2}

Hope it helps!

I'm out!

3 0
2 years ago
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Select the best possible first step to solving the system by first eliminating the x variable.
zheka24 [161]
It seems to be none of the above
3 0
3 years ago
Someone help me please.
Aliun [14]

Answer:

t = 12h

Step-by-step explanation:

t = total

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5 0
3 years ago
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The area of the vegetable garden is 0.4 of the community area of 4.5 x 6.2 . What is the area of the vegetable garden?
Gala2k [10]

Answer:

11.16 units²

Step-by-step explanation:

Area of community area=4.5×6.2= 27.9 units²

Area of vegetable garden=27.9×0.4=11.16 units²

5 0
2 years ago
What is the factored form of x^3-1
polet [3.4K]

Answer:

the factors of x^3-1 are x^3 -1 = (x-1) (x^2 +x+1)\\

Step-by-step explanation:

We need to find factors of x^3 -1

x^3-1 \\(x)^3 -(1)^3\\We \,\, know\,\, a^3 -b^3 = (a-b) (a^2 +ab + y^2) \\So, \,\, using\,\, the \,\, formula\,\,\\Here\,\, a= x \,\,and\,\, b= 1\\(x)^3 -(1)^3 = (x-1) (x^2 +x+1)\\

So, the factors of x^3-1 are x^3 -1 = (x-1) (x^2 +x+1)\\

7 0
3 years ago
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