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stira [4]
3 years ago
8

What is the factored form of the expression? 4x^2-18y^2

Mathematics
2 answers:
Pachacha [2.7K]3 years ago
6 0
Hope this helps
2(2 {x}^{2} - 9 {y}^{2})
Arturiano [62]3 years ago
5 0
I think factored form for your problem should be 2 (2x^2 - 9y^2).  I hope this is what you were asking for sorry if I'm incorrect.  All I did was find the biggest most common factor that they shared which is 2 because 1 is smaller than 2 and 3 doesn't go into 4 and 4 doesn't go into 18.  Finally every number passed 4 wouldn't be able to go into 4.   Welcome
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Find the total area the regular pyramid.
Ber [7]

Answer: 14\sqrt{3}

Step-by-step explanation:

1. You must apply the following formula for calculate  the total surface area the regular pyramid:

SA=\frac{pl}{2}+B

Where p is the perimeter of the base, l is the slant height and B is the area of the base.

2. The perimeter is, where s is the side length:

p=3s=3*4=12

3. The faces are isosceles traingles. So, to find the slant height you can divide one base into two equal right triangles and calculate the slant height with Pythagorean Theorem:

l=\sqrt{4^2-2^2}=2\sqrt{3}

4. The base is equal to any face, then both have equal areas. As previously you divide one base into two equal righ triangle to find the slant height, you can calcualte the area of one right triangle and multply it by 2 to calculate B:

B=2*\frac{bh}{2}=2*\frac{2\sqrt{3}}{2}=2\sqrt{3}

Finally substitute values:

SA=\frac{12*2\sqrt{3}}{2}+2\sqrt{3}=14\sqrt{3}

6 0
3 years ago
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What is ratio of 28 red pens and 84 black pens
Setler [38]
Ratio

28:84

If you want it simplified
it would be
1:3<span />
8 0
4 years ago
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Find the roots of:
Elena-2011 [213]

\large\displaystyle\text{$\begin{gathered}\sf \pmb{1) \  2x^3-7x^2+8x-3=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of -3 are 1, -1, 3, +3. So:

  | 2  -7    8  -3

<u>1 |      2   -5   3</u>

  | 2   -5    3  0

<u> 1 |      2     -3   </u>

    2   -3     0

So the factorization is (x-1)² (2x-3)=0. So:

                     \bf{ x_1=x_2=1 \qquad x_2=\dfrac{3}{2}  }

\large\displaystyle\text{$\begin{gathered}\sf \pmb{2) \  x^3-x^2-4=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:

      |  1  -1  0  -4

  <u>2  |     2  2     </u>

         1  2  2  0

So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.

                   \bf{ 1^2-4(2)(2)=1-16=-15 < 0 \quad \Longrightarrow \quad x=2 }

\large\displaystyle\text{$\begin{gathered}\sf \pmb{3) \  6x^3+7x^2-9x+2=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:

   | 6    7       9      2

<u>-2 |      -12    10     -2</u>

     6    -5     1       0

So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:

         \bf{ x_{2, 3}&=\dfrac{5\pm \sqrt{(5)^2-4(6)(1)}}{2(6)}=\dfrac{5\pm \sqrt{25-24}}{12}=\dfrac{5\pm 1}{12} }}

                     \large\displaystyle\text{$\begin{gathered}\sf  \begin{matrix} x_1=-2&\ \ \ \ \ \ x_{2}=\dfrac{6}{12} \qquad &\ \ \ x_3=\dfrac{4}{12}\\ &\ \ \ x_2=\dfrac{1}{2} \qquad &x_3=\dfrac{1}{3} \end{matrix} \end{gathered}$}

6 0
2 years ago
Plzzz help! will give branliest if you can do this one!!! i also need help with other math problems
kotykmax [81]
I believe it’s the last answer. Rotation of 180 degrees clockwise with a dilation of 5.
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3 years ago
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What is the equation of a line that passes through the points (3,6) and (8,4)?
GrogVix [38]
The equation is y=-2/5x+7 3/5

5 0
3 years ago
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