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timofeeve [1]
3 years ago
13

Suppose we are given the following.

Mathematics
1 answer:
Mashutka [201]3 years ago
6 0

Answer:

Slope of line 1 = 3

Slope of line 2 = -3

Slope of line 3 = -1/3

Line 1 and 2 = perpendicular

Line 1 and 3 = perpendicular

Line 2 and 3 = perpendicular

Step-by-step explanation:

trust me its correct

pls mark me as brainliest

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PLEASE HURRY 10 POINTS What is the solution to the equation 3(2x+5)=3x+4x
Lerok [7]

Answer:

D x=15

Step-by-step explanation:

3(2x+5)=3x+4x

Distribute the 3

6x +15 = 3x+4x

Combine like terms

6x+15 = 7x

Subtract 6x from each side

6x+15 -6x = 7x-6x

15 =x

6 0
3 years ago
Help me please please
yanalaym [24]

Answer:

Hold on a sec i cant remember

3 0
3 years ago
At one point the average price of regular unleaded gasoline was ​$3.39 per gallon. Assume that the standard deviation price per
irinina [24]

This question was not written completely

Complete Question

At one point the average price of regular unleaded gasoline was ​$3.39 per gallon. Assume that the standard deviation price per gallon is ​$0.07 per gallon and use​ Chebyshev's inequality to answer the following.

​(a) What percentage of gasoline stations had prices within 3 standard deviations of the​ mean?

​(b) What percentage of gasoline stations had prices within 2.5 standard deviations of the​ mean? What are the gasoline prices that are within 2.5 standard deviations of the​ mean?

​(c) What is the minimum percentage of gasoline stations that had prices between ​$3.11 and ​$3.67​?

Answer:

a) 88.89% lies with 3 standard deviations of the mean

b) i) 84% lies within 2.5 standard deviations of the mean

ii) the gasoline prices that are within 2.5 standard deviations of the​ mean is $3.215 and $3.565

c) 93.75%

Step-by-step explanation:

Chebyshev's theorem is shown below.

1) Chebyshev's theorem states for any k > 1, at least 1-1/k² of the data lies within k standard deviations of the mean.

As stated, the value of k must be greater than 1.

2) At least 75% or 3/4 of the data for a set of numbers lies within 2 standard deviations of the mean. The number could be greater.μ - 2σ and μ + 2σ.

3) At least 88.89% or 8/9 of a data set lies within 3 standard deviations of the mean.μ - 3σ and μ + 3σ.

4) At least 93.75% of a data set lies within 4 standard deviations of the mean.μ - 4σ and μ + 4σ.

​

(a) What percentage of gasoline stations had prices within 3 standard deviations of the​ mean?

We solve using the first rule of the theorem

1) Chebyshev's theorem states for any k > 1, at least 1-1/k² of the data lies within k standard deviations of the mean.

As stated, the value of k must be greater than 1.

Hence, k = 3

1 - 1/k²

= 1 - 1/3²

= 1 - 1/9

= 9 - 1/ 9

= 8/9

Therefore, the percentage of gasoline stations had prices within 3 standard deviations of the​ mean is 88.89%

​(b) What percentage of gasoline stations had prices within 2.5 standard deviations of the​ mean?

We solve using the first rule of the theorem

1) Chebyshev's theorem states for any k > 1, at least 1-1/k² of the data lies within k standard deviations of the mean.

As stated, the value of k must be greater than 1.

Hence, k = 3

1 - 1/k²

= 1 - 1/2.5²

= 1 - 1/6.25

= 6.25 - 1/ 6.25

= 5.25/6.25

We convert to percentage

= 5.25/6.25 × 100%

= 0.84 × 100%

= 84 %

Therefore, the percentage of gasoline stations had prices within 2.5 standard deviations of the​ mean is 84%

What are the gasoline prices that are within 2.5 standard deviations of the​ mean?

We have from the question, the mean =$3.39

Standard deviation = 0.07

μ - 2.5σ

$3.39 - 2.5 × 0.07

= $3.215

μ + 2.5σ

$3.39 + 2.5 × 0.07

= $3.565

Therefore, the gasoline prices that are within 2.5 standard deviations of the​ mean is $3.215 and $3.565

​(c) What is the minimum percentage of gasoline stations that had prices between ​$3.11 and ​$3.67​?

the mean =$3.39

Standard deviation = 0.07

Applying the 2nd rule

2) At least 75% or 3/4 of the data for a set of numbers lies within 2 standard deviations of the mean. The number could be greater.μ - 2σ and μ + 2σ.

the mean =$3.39

Standard deviation = 0.07

μ - 2σ and μ + 2σ.

$3.39 - 2 × 0.07 = $3.25

$3.39 + 2× 0.07 = $3.53

Applying the third rule

3) At least 88.89% or 8/9 of a data set lies within 3 standard deviations of the mean.μ - 3σ and μ + 3σ.

$3.39 - 3 × 0.07 = $3.18

$3.39 + 3 × 0.07 = $3.6

Applying the 4th rule

4) At least 93.75% of a data set lies within 4 standard deviations of the mean.μ - 4σ and μ + 4σ.

$3.39 - 4 × 0.07 = $3.11

$3.39 + 4 × 0.07 = $3.67

Therefore, from the above calculation we can see that the minimum percentage of gasoline stations that had prices between ​$3.11 and ​$3.67​ corresponds to at least 93.75% of a data set because it lies within 4 standard deviations of the mean.

4 0
3 years ago
Translate each of the following research questions into appropriate H0 and Ha.
Mandarinka [93]

Answer:

a)

H_{0}: \mu = 62500\text{ dollars per year}\\H_A: \mu > 62500\text{ dollars per year}

b)

H_{0}: \mu = 2.6\text{ hours}\\H_A: \mu \neq 2.6\text{ hours}

Step-by-step explanation:

We have to build appropriate null and alternate hypothesis for the given scenarios.

a) Population mean, μ = $62,500 per year

The market research wants to find whether the mean household income of mall shoppers is higher than that of the general population.

H_{0}: \mu = 62500\text{ dollars per year}\\H_A: \mu > 62500\text{ dollars per year}

We would use one-tail(right) test to perform this hypothesis.

b) Population mean, μ = 2.6 hours

The company want to know the average time to respond to trouble calls is different or not.

H_{0}: \mu = 2.6\text{ hours}\\H_A: \mu \neq 2.6\text{ hours}

We would use two-tail test to perform this hypothesis.

7 0
3 years ago
Hey guys i just joined how do i do this
Sergeeva-Olga [200]

Answer: you can ask questions your struggling with and people like me will help you answer them. You can also help other people answer their questions and get points for it

Step-by-step explanation:

7 0
3 years ago
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