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3 years ago

Can someone please help I'm stupid 1.25x - 6.50 > 60

Mathematics

2 answers:

zhenek [66]3 years ago

7 0

Answer:

x>53.2

Step-by-step explanation:

bogdanovich [222]3 years ago

4 0

1.25x-6.50>60

1.25x>60+6.50

1.25x>66.50

1.25x/1.25>66.50/1.25

X>53.2

Answer: X>53.2

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Allison’s cupcake and cookie budget for her party is $105. She would like to have at least 40 cupcakes and cookies combined, and

FinnZ [79.3K]

Answer:

a + b ≥ 40

a + 5 ≤ b

2.50a + 1.50b ≤ 105

Step-by-step explanation:

We are told she would like to have at least 40 cupcakes and cookies combined.

If a is number of cupcakes and b is number of cookies, then this inequality is;

a + b ≥ 40

Secondly, we are told she would like to have at most 5 more cupcakes than cookies.

Thus, the inequality is;

a + 5 ≤ b

Lastly, we are told that cupcakes sell for $2.50 and cookies for $1.50

Thus, the inequality is;

2.50a + 1.50b ≤ 105

Finally, the 3 inequalities are;

a + b ≥ 40

a + 5 ≤ b

2.50a + 1.50b ≤ 105

4 0

3 years ago

What is the square root of 12 simplified? Is it 2 times the square root of 3?

blagie [28]

Answer: Yes, it is $2\sqrt{3}$

Step-by-step explanation:

To simplify square roots, you can factor the number inside the square root into its lowest common denominators.

$\sqrt{12}=\sqrt{4*3} =\sqrt{2*2*3}$

Any value that appears twice can be "taken out" of the square root and moved to the left of it:

$2\sqrt{3}$ ,

What you are doing is essentially taking the square root of 4 and the square root of 3. Because the square root of 4 can be simplified, and the square root of 3 cannot, this is the most simplified version of the expression we can reach.

4 0

3 years ago

Read 2 more answers

How do I find the critical points?

podryga [215]

Critical points is where the derivative (slope) is zero or does not exist. So to do this we have to find the derivative of our function:

$\frac{d}{dx}(x^{2} - 1)^{3}$

So we apply chain rule:

= $3(x^{2} - 1)^{2} * 2x$

Set our first derivative to zero and solve for x:

3(x^2 - 1) * 2x = 0

So we can see that (by plugging in) 0, -1 and 1 makes our solution true

So our critical value is x = 0, x = -1, x = 1

5 0

3 years ago

A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes

Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is $\dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}$

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

$A = \dfrac{7}{4} \cdot a^2 \cdot cot \left (\dfrac{180 ^{\circ}}{7} \right )$

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

$\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}$

$s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69$

$The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52$

The area of the heptagon MNSRQPO is therefore;

$A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94$

$MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times 21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08$

By sine rule, we have

$\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}$

$sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})$

$\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}$

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

$Area \ of \Delta MSQ = \dfrac{1}{2} \times 43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}$

The area of the of the garden plated with flowers, $A_{req}$ , is given as follows;

$A_{req}$ = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

$A_{req}$ = 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, $A_{req}$ ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0

3 years ago

What is the value of k?

Molodets [167]

Answer:

$( {x}^{2} + 16x + 64) - (x + 8)(x - 4) = k(x + 8) \\ ( {x + 8)}^{2} - (x + 8)(x - 4) = k(x + 8) \\ (x + 8) - (x - 4) = k \\ k = (x - x) + (8 + 4) \\ k = 12$

4 0

3 years ago

Read 2 more answers