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svlad2 [7]
3 years ago
7

Explain why a random copolymer is obtained when 3,3-dimethyl-1-butene undergoes cationic polymerization.

Chemistry
1 answer:
dezoksy [38]3 years ago
8 0

Solution :

In the field of chemistry, the cationic polymerization is a kind of the chain growth polymerization where the cation initiator transfers the charge to the monomer and makes it more reactive. This kind of polymerization reaction is very sensitive to the temperature. With increase in temperature, the molecular weight as well as the reaction rate decreases rapidly.

Thus in the cationic polymerization of the 3,3-dimethyl-1-butene, the carbonation intermediate is formed and it rearranges itself. The attack o the 2nd alkene ca take place both the carbonations, so that random copolymer is formed.

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Dafna1 [17]

Explanation:

hope these help you answer

7 0
3 years ago
What volume would 3.01•1023 molecules of oxygen gas occupy at STP?
Sliva [168]
First, find moles of oxygen gas: (3.01 x10^23 molec.)/(6.02 x10^23) =0.5mol O2


Second, multiply moles by the standard molar volume of a gas at STP:(0.5mol)(22.4L) = 11.2L O2
6 0
3 years ago
Two unknown molecular compounds were being studied. A solution containing 5.00 g of compound A in 100. g of water froze at a low
LenaWriter [7]

Answer:

Compound B has greater molar mass.

Explanation:

The depression in freezing point is given by ;

\Delta T_f=i\times k_f\times m..[1]

m=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Mass of solvent in kg}}

Where:

i = van't Hoff factor

k_f = Molal depression constant

m = molality of the solution

According to question , solution with 5.00 g of A in 100.0 grams of water froze at at lower temperature than solution with 5.00 g of B in 100.0 grams of water.

The depression in freezing point of solution with A solute: \Delta T_{f,A}

Molar mass of A = M_A

The depression in freezing point of solution with B solute: \Delta T_{f,B}

Molar mass of B = M_B

\Delta T_{f,A}>\Delta T_{f,B}

As we can see in [1] , that depression in freezing point is inversely related to molar mass of the solute.

\Delta T_f\propto \frac{1}{\text{Molar mass of solute}}

M_A

This means compound B has greater molar mass than compound A,

4 0
3 years ago
A liquid solvent is added to a flask containing an insoluble solid. The total volume of the solid and liquid together is 80.0 mL
Lyrx [107]

Answer:

111.44 g

Explanation:

We'll begin by calculating the volume of the solvent. This can be obtained as follow:

Mass of solvent = 21 g

Density of solvent = 0.865 g/mL.

Volume of solvent =?

Density = mass /volume

0.865 = 21 /volume of solvent

Cross multiply

0.865 × volume of solvent = 21

Divide both side by 0.865

Volume of solvent = 21 / 0.865

Volume of solvent = 24.28 mL

Next, we shall determine the volume of the solid. This can be obtained as follow:

Volume of solvent + solid = 80.0 mL.

Volume of solvent = 24.28 mL

Volume of solid =?

Volume of solid = (Volume of solvent + solid) – (Volume of solvent)

Volume of solid = 80 – 24.28

Volume of solid = 55.72 mL

Finally, we shall determine the mass of the solid. This can be obtained as follow:

Density of solid = 2.00 g/mL.

Volume of solid = 55.72 mL

Mass of solid =.?

Density = mass / volume

2 = mass of solid / 55.72

Cross multiply

Mass of solid = 2 × 55.72

Mass of solid = 111.44 g

Therefore, the mass of the solid is 111.44 g

8 0
3 years ago
True or False
goldenfox [79]

Answer:

I believe its True

4 0
3 years ago
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