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bulgar [2K]
3 years ago
10

A solution of potassium chlorate, KCIO3, has 20 grams of the

Chemistry
1 answer:
natima [27]3 years ago
7 0

C) 10 grams

Explanation:

Potassium chlorate (KCIO₃) have a solubility in water at 70 °C of 30 grams in 100 grams of water.

If our solution have already 20 grams of potassium chlorate salt dissolved that means we need another 10 grams of potassium chlorate to reach the saturation point.

Learn more:

Potassium chlorate solubility in water

brainly.com/question/10140327

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What mass of O2, in grams, is required to completely react with 0.025 g C3H8?
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2C3H8+ 702--->6CO2+8H20
FROM  Equation  above  2  moles of C3H8    reacted with  7  moles  of oxygen  to  form   6  moles of  c02 plus  8  molesof  H2O  
the  moles  of  c3H8  reacted is = MASS/ R.F.M
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3 years ago
The oxidation of copper(I) oxide, Cu2O(s) , to copper(II) oxide, CuO(s) , is an exothermic process. 2Cu2O(s)+O2(g)⟶4CuO(s) The c
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Answer:

The work is  

      W = -0.369kJ

The energy  change of the reaction is  \Delta U _{rxn} = 43.839 kJ  

Explanation:

From the question we are told that

    The chemical equation for this reaction is

             2 Cu_2 O + O_2_{(g)} ----> 4 CuO_{(s)}

     The mass of  Cu_2 O is  m = 42.60g

      The enthalpy Cu_2 O is  \Delta H_{re} = -43.47 \ kJ this also the change in energy in terms of heat

      The pressure at which it is oxidized is P = 1\  bar

The  no of moles of Cu_2 Oused in this reaction is mathematically represented as

        n = \frac{mass \ of   \ Cu_2 O}{Molar \ mass \  of   \ Cu_2 O}

The molar mass of Cu_2 O is  a constant with a value  M = 143.1 g/mol

   Now substituting values

             n = \frac{ 42.60}{143.1}

            n = 0.29769 \ moles

From the reaction we see that

Two mole of Cu_2 O  reacts with One mole of O_2 to give Four moles of  CuO_{(s)}

This means that

One mole of  Cu_2 O  reacts with 0.5 mole of O_2 to give two moles of  CuO_{(s)}

it also implies that

0.29769 \ mole of  Cu_2 O  reacts with 0.5 * 0.29769 moles of O_2 to give 2* 0.29769 moles of  CuO_{(s)}

so

0.29769 \ mole of  Cu_2 O  reacts with 0.149 moles of O_2 to give 0.595 moles of  CuO_{(s)}

Now the number of moles of gaseous reactant is

      N_{O_2} = 0.149 \ moles

The number of moles of gaseous product  is

     N_p = 0 \ moles

So the change in number of moles for gaseous  compounds is mathematically evaluated as

         \Delta N = 0- 0.149 \ moles

        \Delta N = - 0.149 \ moles

Now the workdone for  the compound Cu_2 O is mathematically represented as

        W = \Delta N RT

Where R is the gas constant with a value of R = 8.314 J/mol \cdot K

            T is the temperature with a value  T = 25 + 273 = 298 K

     Substituting values

     W = -0.149 * 8.314 * (298)

     W = -0.369kJ

Generally the internal energy change of the reaction can be represented as

           \Delta U _{rxn} = \Delta H_{re} - W

Substituting value

        \Delta U _{rxn} = -43.47 -  (-0.369)

        \Delta U _{rxn} = 43.839 kJ  

This is the internal energy change on the reaction for 42.60 g of Cu_2 O

       

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