Answer:
I hope this is helpful
Step-by-step explanation:
mark brainlest pls
1.divide the first term of the numerator by the first team of the denominator, and put that in the answer
2. Multiply the denominator by that answer, put that below the numerator
3.subtract to create a new polynomial
All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

Multiply both sides by <em>r</em> :

Subtract the latter sum from the first, which eliminates all but the first and last terms:

Solve for
:

Then as gets arbitrarily large, the term
will converge to 0, leaving us with

So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18
20/5=4
25/7=<span>3.57142857143 Rounded to the nearest tenth: 3.6
4>3.6
If you want the nearest whole, you would round down to 3 because you would be short of 4.
3<4 </span>
Answer:
a = -1/2
Step-by-step explanation:
- 1/4a - 4 = 7/4a - 3
- 1/4a - 7/4a = - 3 + 4
- 8/4a = 1
- a = 1 / 8/4
- a = 1 * 4/8
- a = 4/8
- a = 1/2
a = - 1/2