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Delvig [45]
3 years ago
8

Maya is the manager for the track team. She created a table to compare finish times from the second practice to the first practi

ce. 100 m Dash Finish Time Comparison Runner Second practice time compared to first practice time Joshua +1.03 Kedwin –0.97 Leila –0.95 Miguel +1.1 Nicole –0.87 Maya claims that the runners’ order of most improved to least improved is Miguel, Joshua, Nicole, Leila, and Kedwin. Which statement describes whether Maya is correct? Maya is correct because she compared each digit in the same place value. Miguel added the most time to his sprint so he is most improved. Maya is incorrect because –0.87 < –0.95 < –0.97. Runners that decrease times are improving, and those that add time are not improving. Maya is incorrect because 1.1 < 1.03. She should switch the order of Joshua and Miguel because Joshua added more time to his run. Maya is incorrect because she listed the runners from least improved to most improved. Runners that decreased times are improving, and those that add time are not improving.
Mathematics
1 answer:
Neko [114]3 years ago
6 0

Answer:

D. Maya is incorrect because she listed the runners from least improved to most improved. Runners that decreased times are improving, and those that add time are not improving.

Step-by-step explanation:

I got it right on edge

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What is the definition of A net (of a shape)
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Read 2 more answers
The value of -4 2 is _____. pls help
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What two rational expressions sum to 3x+4/x^2-6x+5?
Lubov Fominskaja [6]

Answer:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

Step-by-step explanation:

The given rational expression is:

\frac{3x+4}{x^{2}-6x+5} = \frac{3x+4}{(x-1)(x-5)}

We can use concept of Partial Fractions to solve this problem. Let,

\frac{3x+4}{(x-1)(x-5)}=\frac{A}{x-1} +\frac{B}{x-5}

Multiplying both sides by (x - 1)(x - 5), we get:

3x+4=A(x-5)+B(x-1)

Substituting x = 5, we get:

3(5)+4=A(5-5)+B(5-1)\\\\ 15+4=0+4B\\\\ 19=4B\\\\ B=\frac{19}{4}

Substituting x = 1, we get:

3(1)+4=A(1-5)+B(1-1)\\\\ 7=-4A\\\\ A=-\frac{7}{4}

Substituting the value of A and B, back in the original equation, we get:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

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3 years ago
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