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padilas [110]
3 years ago
5

Which is a Quadratic ?

Mathematics
1 answer:
Liula [17]3 years ago
3 0

Answer:7uu

lol

Step-by-step explanation:

ssssy6

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The table below shows the number of ounces in price for each of the four different bottles of orange juice. Which bottle has a p
sleet_krkn [62]

Answer:

12 oz bottle

Step-by-step explanation:

See attached image.

4 0
3 years ago
A bookstore had 60 copies of a magazine. Yesterday, it sold 1/4 of them. Today, it sold 2/3 of what remained. How many copies do
Inga [223]
The bookstore has 4 copies left
8 0
3 years ago
Read 2 more answers
Please help! I have 35 minutes left! You can get 100 points!
Stella [2.4K]

Answer:

The expression equivalent to 8 - (6r + 2) is -6r + 6 ⇒ A

Step-by-step explanation:

Let us solve the question

∵ The expression is 8 - (6r + 2)

→ Multiply the bracket by (-)

∵ (-) × (+) = (-)

∴ 8 - (6r + 2) = 8 - 6r - 2

→ Add the like terms

∵ 8 - (6r + 2) = (8 - 2) - 6r

∴ 8 - (6r + 2) = 6 - 6r

→ Switch the terms

∴ 8 - (6r + 2) = -6r + 6

∴ The expression equivalent to 8 - (6r + 2) is -6r + 6

7 0
4 years ago
The vertices of the trapezoid are J(4m, 4n), K(4q, 4n), M(4p, 0), and L(0, 0). Find the midpoint of the midsegment of the trapez
Lilit [14]
To get the midsegment, namely HN, well, we need H and N

hmm so....  notice the picture you have there, is just an "isosceles trapezoid", namely, it has two equal sides, the left and right one, namely JL and KM

the midpoint of JL is H and the midpoint of KM is N

thus

\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ \square}}\quad ,&{{ \square}})\quad 
%  (c,d)
&({{ \square}}\quad ,&{{ \square}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)\\\\
-----------------------------\\\\

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
J&({{ 4m}}\quad ,&{{ 4n}})\quad 
%  (c,d)
L&({{ 0}}\quad ,&{{ 0}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{0+4m}{2}\quad ,\quad \cfrac{0+4n}{2} \right)
\\\\\\
\left( \cfrac{4m}{2},\cfrac{4n}{2} \right)\implies \boxed{(2m,2n)\impliedby H}\\\\
-----------------------------\\\\

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
K&({{ 4q}}\quad ,&{{ 4n}})\quad 
%  (c,d)
M&({{ 4p}}\quad ,&{{ 0}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{4p+4q}{2}\quad ,\quad \cfrac{0+4n}{2} \right)
\\\\\\
\left( \cfrac{2(2p+2q)}{2},\cfrac{4n}{2} \right)\implies \boxed{[(2p+2q), 2n]\impliedby N}\\\\
-----------------------------\\\\

\bf \textit{so, the midpoint of HN is }
\\\\\\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
H&({{ 2m}}\quad ,&{{ 2n}})\quad 
%  (c,d)
N&({{ 2p+2q}}\quad ,&{{ 2n}})
\end{array}\\\\\\
%   coordinates of midpoint 
\left(\cfrac{(2p+2q)+2m}{2}\quad ,\quad \cfrac{2n+2n}{2} \right)
\\\\\\
\left( \cfrac{2(p+q+m)}{2},\cfrac{4n}{2} \right)\implies (p+q+m)\quad ,\quad 2n
5 0
3 years ago
Read 2 more answers
What shows the volume
Svetllana [295]

Answer:

654 1/2 cm³

Step-by-step explanation:

First the volume of the cylinder, the formula for that is πr²h

Radius is half of diameter so 7/2=3.5

3.5^2=12.25

12.25x22/7=38.5

38.5x15=577.5

Now the cone, the formula for this is πr²h/3

It has the same radius as the cylinder so 3.5^2=12.25

12.25x22/7=38.5

38.5x6=231

231/3=77

Now we add them together to find total volume.

577.5+77=654.5


8 0
4 years ago
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