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3 years ago

10

Answer this simple quick question!! Pls :) m

2 answers:

notka56 [123]3 years ago

7 0

Answer:

Answer is B!

Step-by-step explanation:

58 * 20 = 1160

0+160= 160

160+1000=1160

Olenka [21]3 years ago

6 0

Answer:

B

Step-by-step explanation:

58 * 20 is 1160 and 0 + 160 + 1000 = 1160

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How many solutions does the equation x_1 +x_2+x_3+x_4+x_5=21 have where x_1, x_2, x_3, x_4, and x_5 are nonnegative integers and

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Step-by-step explanation:

$x_{1} + x_{2} + x_{3} + x_{4} + x_{5} = 21\\$ (given)

Let us consider :

$x_{1}$ = $t_{1} + 1$

$x_{2}$ = $t_{2}$

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Now, by substituting the above considerations in the above equation, we get:

$t_{1} + 1 + t_{2} + t_{3} + t_{4} + t_{5} = 21\\$

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where,

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then it follows

n = 20

r = 4

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= $_{4}^{24}\textrm{C}$

= 10626

Answer :

no. of solutions for the eqn 10626

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