M∠LON=77 ∘ m, angle, L, O, N, equals, 77, degrees \qquad m \angle LOM = 9x + 44^\circm∠LOM=9x+44 ∘ m, angle, L, O, M, equals, 9,
timama [110]
Answer:
Step-by-step explanation:
Given
<LON = 77°
<LOM = (9x+44)°
<MON = (6x+3)°
The addition postulate is true for the given angles since tey have a common point O:
<LON = <LOM+<MON
Since we are not told what to find we can as well look for the value of x, <LOM and <MON
Substitute the given parameters and get x
77 = 9x+44+6x+3
77 = 15x+47
77-47 = 15x
30 = 15x
x = 30/15
x = 2
Get <LOM:
<LOM = 9x+44
<LOM = 9(2)+44
<LOM = 18+44
<LOM = 62°
Get <MON:
<MON = 6x+3
<MON = 6(2)+3
<MON = 12+3
<MON = 15°
Answer: y=-4x+7
Step-by-step explanation: Move 8x to the right side to isolate y. 2y=14-8x. Divide the whole equation by 2 to get y by itself. y=7-4x
Difference of two squares is of the form (a + b)(a - b) or vice-versa. Here, a = -5x and b = 3.
(-5x - 3)(-5x + 3)
Answer: 3
Answer:
(0,0), (−6,6) ,(0,9), (8,6), (1,2), (3,4)
Step-by-step explanation:
these are the coordinates just put in on the graph
hope that helps
