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Feliz [49]
3 years ago
14

Does anyone know this

Mathematics
1 answer:
Rudik [331]3 years ago
6 0
The vertex is (-1,2) thats all i know
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Shanti began to draw a Venn diagram comparing refracting and reflecting telescopes. 2 overlapping circles. The left circle label
iren2701 [21]

The label could be written in the area marked X as "Uses a convex eyepiece lens". Then the correct option is D.

<h3>What are Sets?</h3>

Sets are the collection of well-defined elements. A set is represented by a capital letter symbol and the number of elements in the finite set is shown as curly bracket {..}.

<h3>What is the Venn diagram?</h3>

It is the representation of the sets by the diagram. And shows the condition that is generated between them by the overlapping of the circle.

Shanti began to draw a Venn diagram comparing refracting and reflecting telescopes. The two overlapping circles.

The left circle is labeled Refracting telescopes.

The right circle is labeled Reflecting Telescopes.

An X in the overlap. Both as a label below and outside the overlap.

From the figure, we can say that the label could be written in the area marked X as "Uses a convex eyepiece lens".

Then the correct option is D.

More about the set link is given below.

brainly.com/question/8053622

7 0
2 years ago
Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re
fiasKO [112]

Answer: R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts 38^{\circ} angle to each other

The resultant of the two forces is given by

\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}

Insert the values

\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb

Resultant makes an angle of

\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}

So, the resultant makes an angle of 22.57^{\circ} with 9 lb force

Angle made with 13 lb force is 38^{\circ}-22.57^{\circ}=15.43^{\circ}

7 0
3 years ago
Read 2 more answers
Directions: Calculate the percent increase or decrease between the starting and ending
valentinak56 [21]

Answer:233.333%

Step-by-step explanation:

1. 10-3=7 subtract end by start

2.7/3=2.333 divide difference by absolute value of start

32.333x100=233.333% multiply by 100 if negative its decreasing if positive it increasing

hoped this helped

8 0
3 years ago
Read 2 more answers
In the figure below, the segments overline RS and overline RT are tangent to the circle centered at Given that OS = 3.6 and RT =
ExtremeBDS [4]

Answer:

RS = 4.8

OT = 3.6

From the Pythagorean Theorem we know:

OR^2 = ST^2 + OT^2

OR^2 = 4.8^2 + 3.6^2

OR ^2 = 23.04 + 12.96

OR^2 = 36

OR = 6

Step-by-step explanation:

8 0
3 years ago
Plz help fasttttttttt
ser-zykov [4K]

Answer:

i cant read it

Step-by-step explanation:

maby inhance the image

8 0
3 years ago
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