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Anastasy [175]
3 years ago
6

Pls help it is easy but i did not understand it

Mathematics
1 answer:
Vikki [24]3 years ago
5 0

Answer:

I guess the answer would be

Step-by-step explanation:

\frac{3}{4}

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130% of what number is 208?
ozzi
1. 208/x = 100/130
2. multiply both sides by x
3. 208 = 0.76923x
4. divide both sides by 0.76923
5. x = 270.4
8 0
3 years ago
Calculate the book value of a new maxi taxi costing $44000 after 5 years if it depreciates each year by 13% a. $22,930.52 b. $21
Marat540 [252]

Answer:

A=$21930.52

Step-by-step explanation:

Given data

Principal =44000

Time =5years

Rate of depreciation =13%

The expression for the depreciation is

A=P(1-r)^t

Substitute

A=44000(1-0.13)^5

A=44000(0.87)^5

A=44000*0.4984209207

A=21930.52

3 0
3 years ago
Pleaseee helpppppp!!!
Gnesinka [82]

Answer:

y=3/2

Step-by-step explanation:

6 0
3 years ago
Suppose that the given line has a slope of -2/3 and a y-intercept of (0,5/3). which of the following points is also a solution t
otez555 [7]

Answer:

From five given points it is find that points (1 , 1) and (4 , -1) will apply

Step-by-step explanation:

According to question,

Slop of line (m) = \frac{-2}{3}

And y-intercept is ( 0, \frac{5}{3})

So from above slope and points, the equation of line can be written as

y = mx + c

i.e \frac{5}{3} = \frac{-2}{3} x + c

    \frac{5}{3} = \frac{-2}{3} (0) + c

    \frac{5}{3} = 0 + c

Or, c = \frac{5}{3}

A) With points ( 5, \frac{5}{3} )

   At x = 5, y =\frac{-2}{3} (5) + \frac{5}{3}

            or, y = \frac{-10}{3} + \frac{5}{3}

            so, y = \frac{-5}{3}

Hence this points do not apply

B) With points ( 1 , 1 )

   At x = 1, y =  \frac{-2}{3} (1) +  \frac{5}{3}

      or,      y =  \frac{-2+5}{3}

      So,     y =  \frac{3}{3}

                y = 1

Hence this points will apply

C) With points ( 4 , -1 )

    At x = 4 , y =  \frac{-2}{3} (4) +  \frac{5}{3}

                    y =  \frac{-8+5}{3}

                    y =  \frac{-3}{3}

             So,  y= -1

Hence this points will apply

D) With points (-3 ,7)

    At x = - 3, y = \frac{-2}{3} (-3) +  \frac{5}{3}

                     y = \frac{14}{3}

 Hence this point will not apply

E) with points (0 , 0)

    At x 0,     y =  \frac{-2}{3} (0) +  \frac{5}{3}

               Or, y = 0 +  \frac{5}{3}

                     y =  \frac{5}{3}

Hence this point will not apply

∴ From above five given points it is find that points (1 , 1) and (4 , -1) apply

Answer

7 0
3 years ago
Help please No links And with explanation please!
victus00 [196]
First: -8 second:17
4 0
3 years ago
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