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IrinaVladis [17]
3 years ago
15

A cubic yard is what kind of measurement?

Mathematics
2 answers:
lesantik [10]3 years ago
8 0
Option C
Volume/Capacity
Nat2105 [25]3 years ago
5 0
I think it is B
Hope this help you????
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Help help please.....Thanks
Novosadov [1.4K]

Hey there! :)

Answer:

56.7 kg.

Step-by-step explanation:

Use the density formula to solve for the mass:

D = m/V.

Rearrange in terms of mass, or 'm':

DV = m.

Solve for the volume:

0.06 × 0.9 × 1.5 = 0.081 m³.

Plug this into the equation along with the density:

700 × 0.081 = 56.7 kg.

5 0
3 years ago
Can you show me what line cd looks like
fgiga [73]
Um I can't answer without an image
3 0
3 years ago
A quiz consist of 2 true-or-false questions 3 are multiple choice questions. The multiple choice questions have 3 options each.
Ahat [919]
Part 1: 2×2×3×3×3=108 (c)
Part 2: 10×9×26×25×4=234000 (c)
Part 3: 10×9×8×7×6×5×4×3×2×1÷(3×2×1)=604800 (d)
Part 4: 11C4=11×10×9×8÷(4×3×2×1)=330 (a)
Part 5: ⅕=20% (c)
Part 6: 100-2.9=97.1 (d)
4 0
3 years ago
a wildlife manager determines that the function y=200x1.07* represents the deer population at a state park x years after the pop
Kobotan [32]

Answer:

Table:

0,200

4, 262

8,344

12, 450

Population after 12 years is 450 deer

Initial population is 200 deer.

Step-by-step explanation:

You take the x in the table and plug it in as an exponent so you will need a calculator or multiple the 1.07 by that many times so 1.07 12 times multipled by itself. and the initial is 0 years so anything to the exponent of 0 is 1 so that show i got 200 for the x=0

8 0
3 years ago
weekly wages at a certain factory are normally distributed with a mean of $400 and a standard deviation of $50. find the probabi
kenny6666 [7]

Answer:

0.34134

Step-by-step explanation:

In other to solve for this question, we would be using the z score formula

z = (x - μ) / σ

x = raw score

μ = mean

σ = Standard deviation

We are told in the question to find the probability that a worker selected at random makes between $350 and $400

let x1 = 350 and x2= 400 with the mean μ = 400 and standard deviation σ = $50.

z1 = (x1 - μ) / σ = (350-400) / 50 = -1

z2 = (x2 - μ) / σ = (400 - 400) / 50 = (0/50) = 0

From tables, P(z <= -1) = 0.15866

P(z <= 0) = 0.5

Then, the probability would give us, P(-1 ≤ z ≤ 0) =0.5 - 0.15866 =

0.34134

Hence, The probability that a worker selected at random makes between $350 and $400 = 0.34134

7 0
3 years ago
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