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timofeeve [1]
3 years ago
8

lass="latex-formula">
​
Mathematics
1 answer:
allochka39001 [22]3 years ago
5 0

Step-by-step explanation:

Sin(A+B) = Sin A Cos B + Cos A Sin B.

Sin 75 = Sin ( 45 + 30) = Sin 45 Cos 30 + Cos 45 Sin 30. Sin 75 = (1 / √2) ( √3 / 2) + (1 / √2) ( 1 / 2) = [ √3 + 1] / 2√2.

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Which equation does the graph below represent <br> !!!NEED HELP ASAP!!!
ella [17]

Answer:

im pretty sure its -4

Step-by-step explanation:

you cant really hold me to it but its -1/4 or -4

4 0
3 years ago
Read 2 more answers
during a hike, 3 friends equally shared 1/2 pound of trail mix. what amount of trail mix, in pounds, did each friends recieve
VashaNatasha [74]
1/2 divided by 3 is 1/6.
So your answer is 1/6 pounds each person.
7 0
3 years ago
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Brian ate 2/3 of a pizza. His friend, Joseph, ate 1/4 of what was left. How much pizza did Joseph eat?
Natasha_Volkova [10]

Answer:

1/12

Steps:

1 - 2/3 = 1/3

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3 0
3 years ago
Una diseñadora de modas que confecciona trajes de noche, tarda 3 horas en cortar y 2 horas en coser cada vestido de fiesta. Para
ella [17]

For this case we define the following variables:

x: Number of party dresses

y: Number of suits

You have 30 hours per week to cut, that is, the first equation is given by:

3x + 3y = 30\\

It is also known that 25 hours per week are available for sewing, that is:

2x + 3y = 25\\

It has a system of two equations with two unknowns, solving we have:

3x + 3y = 30\\\\2x + 3y = 25\\

Multiplying the second equation by -1:

3x + 3y = 30\\\\-2x-3y = -25\\

Adding up:

x + 0 = 5\\\\x = 5\\

Substituting x in the first equation:

3 * 5 + 3y = 30\\\\15 + 3y = 30\\

Clearing and:

3y = 30-15\\\\3y = 15\\

y = \frac{15}{3}\\\\y = 5\\

Thus, per week, the designer can produce 5 party dresses and 5 suits working at her maximum capacity.

Answer:

5 Party dresses

5 Suits


5 0
3 years ago
The function V=25000\left(0.82\right)^tV=25000(0.82) t models the depreciation of the value of a new car that originally cost $\
alekssr [168]

Answer:

V = 7,600.17

Step-by-step explanation:

Given:

V=25000(0.82)^t

Where,

V = value of the car

t = time in years

Find V when t = 6

V = 25,000(0.82)^t

= 25,000(0.82)^6

= 25,000(0.304006671424)

= 7,600.1667856

Approximately

V = 7,600.17

4 0
3 years ago
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