Answer:
![2x^2-2x+7](https://tex.z-dn.net/?f=2x%5E2-2x%2B7)
Step-by-step explanation:
First rearrange the equation so all similar variables are together (all the
all the x's and all the numbers without an x)
![3x^2-x^2+6x-8x-4+11](https://tex.z-dn.net/?f=3x%5E2-x%5E2%2B6x-8x-4%2B11)
Then do addition and subtraction
![3x^2-1x^2=2x^2\\6x-8x=-2x\\and\\-4+11=7\\](https://tex.z-dn.net/?f=3x%5E2-1x%5E2%3D2x%5E2%5C%5C6x-8x%3D-2x%5C%5Cand%5C%5C-4%2B11%3D7%5C%5C)
Then we put it all together to get the finally result of ![2x^2-2x+7](https://tex.z-dn.net/?f=2x%5E2-2x%2B7)
Answer: *See attachment*
I'll have to ask you to excuse my handwriting- I had to write pretty fast.
Anyway, I hope this helps!
LaciaMelodii :)
Answer:
(x-3)(x-9)
Step-by-step explanation:
first thing you need to do is move the -6 over. so we're going to add 6 to both sides (we add because it's negative 6 and we need 0 on the right side)
so you have: x^2-12x+27
now we need to come up with two numbers that add to -12 and multiply to 27.
the factors of 27 are 9 & 3 and 27 & 1. only 9 & 3 add to 12 so we are going to use those.
since the 12 is negative however, 9 and 3 should both be negative.
therefore we get: (x-3)(x-9)
*it doesn't matter which order you put them in!