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Ilya [14]
3 years ago
8

HEy i need to know what 2x+5=10 solve for x

Mathematics
2 answers:
Mama L [17]3 years ago
8 0
X=2.5

subtract 5 from both sides and then divide 5 by 2.
konstantin123 [22]3 years ago
7 0
X=5/2 or 2.5 that is in decimal form
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Find the distance between the points (-3, 11) and (5, 5).<br><br> 10<br> 2<br> 2
yanalaym [24]
Use the distance formula to find the distance between two points.

d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

d= \sqrt{(-3-5)^2+(11-5)^2} \\ d - \sqrt{-8^2+6^2} \\ d=\sqrt{64+36} \\ d = \sqrt{100} \\\\ \boxed{d=10}
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4 years ago
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Question 3.<br> How do you write 4% as a decimal?<br> A) 0.4<br> B) 0.40<br> C) 0.04
AnnyKZ [126]
C. 0.04 would be the correct answer.
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3 years ago
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An island is 1 mi due north of its closest point along a straight shoreline. A visitor is staying at a cabin on the shore that i
Elanso [62]

Answer:

The visitor should run approximately 14.96 mile to minimize the time it takes to reach the island

Step-by-step explanation:

From the question, we have;

The distance of the island from the shoreline = 1 mile

The distance the person is staying from the point on the shoreline = 15 mile

The rate at which the visitor runs = 6 mph

The rate at which the visitor swims = 2.5 mph

Let 'x' represent the distance the person runs, we have;

The distance to swim = \sqrt{(15-x)^2+1^2}

The total time, 't', is given as follows;

t = \dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}

The minimum value of 't' is found by differentiating with an online tool, as follows;

\dfrac{dt}{dx}  = \dfrac{d\left(\dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}\right)}{dx} =  \dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} }

At the maximum/minimum point, we have;

\dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} } = 0

Simplifying, with a graphing calculator, we get;

-4.72·x² + 142·x - 1,070 = 0

From which we also get x ≈ 15.04 and x ≈ 0.64956

x ≈ 15.04 mile

Therefore, given that 15.04 mi is 0.04 mi after the point, the distance he should run = 15 mi - 0.04 mi ≈ 14.96 mi

t = \dfrac{14.96}{6} +\dfrac{\sqrt{(15-14.96)^2+1^2}}{2.5} \approx 2..89

Therefore, the distance to run, x ≈ 14.96 mile

6 0
3 years ago
Find an equation of the line that passes through the point (-6,7) and is perpendicular to the line 12x-18y-72=0
madreJ [45]

Answer:

y=-1.5x-2

Step-by-step explanation:

18y=12x-72

3y=2x-12

y=2/3x-4

Slope=-1.5

7=-6(-1.5)+b

7=9-2

4 0
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A total of raffle tickets were sold at a school fair
Elis [28]

Answer:

ok and what else there is 80 percent left

Step-by-step explanation:

6 0
3 years ago
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