METHOD 1
f(3) = 20
f(4) = 30
f(5) = 42
f(6) = 56
rate of change
f(4)-f(3)=10
f(5)-f(4)=12
f(6)-f(5)=14
then the average of change is 10+12+14 /3 = 12
METHOD 2 --- faster
rate of change = f(6)-f(3) / 6-3
= (36+18+2)-(9+9+2) / 3
= 36/3 = 12
Answer:
The equation of straight line is x = 1
Step-by-step explanation:
<u>Step </u>:-
The equation of straight line having slope 'm' and passing through the point
is 
Slope of horizontal line(that is x-axis) is m = 0
slope of vertical line (that is y-axis) is m is not defined
The equation of straight line having slope is not defined and passing through the point (1,7).

cross multiplication we will get equation

x-1 = 0
The equation of straight line is x = 1
-(17/30)n^5+(113/12)n^4-(173/3)n^3+ (1915/12) n^2- ( 5813/30)n +85
there fore term number 7 is .... -146/1=-146
Answer:
Step-by-step explanation:
fog(x)=f(g(x))
=f(x+2)
=3⋅(x+2)
=3x+6
gof(x)=g(f(x))=g(3x)
=3x+2
gof(2)=3⋅2+2
=6+2
=8
fog(2)=3⋅(2+2)
=3*2+6=12
Answer:
40×3 =120
2×60=120
Step-by-step explanation: have a good day