A 90% confidence interval is found to be (72,78) what is the margin of error

We played 15 games. We have two times as many losses as wins. How many wins do we have?

Hunter-Best [27]

I'd say the answer is 5 wins
hope this helps

8 0

3 years ago

How to be a successful student?

SashulF [63]

Answer:

If you want to be a successful student, read below! :)

Step-by-step explanation:

First, listen to the teacher.

Second, don't be late.

Third, don't talk back.

Fourth, don't be disrespectful.

Fifth, don't cause commotions on purpose.

Sixth, do your assignments/tests/quizzes on time

If your teacher is normal, then these tips should help, I am the top student in my class and this is what I do.

Hope this helped!

5 0

3 years ago

Read 2 more answers

(K-10) divided by 2 = -7<br><br> What’s the answer for the variable k?

stira [4]

Answer:

k = -4

Step-by-step explanation:

(k - 10)/2 = -7

First: multiply by 2 to get rid of the denominator

2(k - 10)/2 = 2(-7)

k - 10 = -14

Next: add 10 to both sides to isolate k

k - 10 + 10 = -14 + 10

k = -4

7 0

4 years ago

About 10% of people in the United States are left handed. Suppose we take a sample of 120 U.S. Residents, and let X = the number

olganol [36]

Answer:

1) $E(X) = np = 120*0.1 =12$

$SD(X) = \sqrt{np(1-p)}= \sqrt{120*0.1*(1-0.1)} =3.286$

For this case we can interpret that the expected variation around the mean is about 3.3 people approximated

2) $P(X\geq 16)$

And we can use the normal approximation given by:

$X \sim N(12, \sigma =3.286)$

And we can use the z score formula given by:

$z = \frac{X -\mu}{\sigma}$

And if we find the z score for 16 we got:

$z = \frac{16-12}{3.286}= 1.217$

And we can find this probability using the normal standard distribution or excel and we got:

$P(Z>1.217) = 0.112$

3) For this case we can conclude that the probability to find 16 or more individuals left handed in a sample of 120 is about 0.112 or 11.2%

Step-by-step explanation:

Let X represent the random variable for the number of residents who are left handed

And for this case we can model this variable with this distirbution:

$X\sim Binom(n= 120 , p =0.1)$

Part 1

The mean is given by:

$E(X) = np = 120*0.1 =12$

And the deviation would be:

$SD(X) = \sqrt{np(1-p)}= \sqrt{120*0.1*(1-0.1)} =3.286$

For this case we can interpret that the expected variation around the mean is about 3.3 people approximated

Part 2

We want to calculate this probability:

$P(X\geq 16)$

And we can use the normal approximation given by:

$X \sim N(12, \sigma =3.286)$

And we can use the z score formula given by:

$z = \frac{X -\mu}{\sigma}$

And if we find the z score for 16 we got:

$z = \frac{16-12}{3.286}= 1.217$

And we can find this probability using the normal standard distribution or excel and we got:

$P(Z>1.217) = 0.112$

Part 3

For this case we can conclude that the probability to find 16 or more individuals left handed in a sample of 120 is about 0.112 or 11.2%

7 0

3 years ago

Find the vertex and the axis of symmetry of the graph of y=-6(x+4)^2 – 3.

vesna_86 [32]

Answer:

vertex = (- 4, - 3 ), equation is x = - 4

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

y = 6(x + 4)² - 3 ← is in vertex form

with (h, k ) = (- 4, 3 ) ← vertex

The equation of the axis of symmetry is a vertical line passing through the vertex, with equation

x = - 4

4 0

3 years ago