3 years ago

I NEED REAL HELP QUICKLY please

Mathematics

2 answers:

skad [1K]3 years ago

6 0

Answer:

hold on its its.............oh yeah 21

Anna11 [10]3 years ago

4 0

Answer:

Step-by-step explanation:

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The larger of two consecutive odd integers is four less than three times the smallest integer. Find the two integers.

ElenaW [278]

Answer: -1 and 1

Step-by-step explanation:

Let the first integer be x and the second x +2 , clearly, the larger is x + 2.

From the statement given

x + 2 = 3x + 4

x - 3x = 4 - 2

-2x = 2

x = -1

The second integer is -1 + 2 = 1

4 0

3 years ago

Write 14/√2 + √50 in the form b√2 where b is an integer.

kifflom [539]

Answer:

$12 \sqrt{2}$

Step-by-step explanation:

Taking the terms one at a time,

$\frac{14}{ \sqrt{2} } \\ \frac{14 * \sqrt{2} }{ \sqrt{2} * \sqrt{2} } \\ \frac{14 \sqrt{2} }{2} \\ 7 \sqrt{2}$

$\sqrt{50} \\ \sqrt{25 * 2} \\ \sqrt{25}* \sqrt{2} \\ 5 * \sqrt{2} \\ 5 \sqrt{2}$

Adding the terms, you have;

$7 \sqrt{2} + 5 \sqrt{2} =(7 + 5) \sqrt{2} = 12 \sqrt{2}$

Hope it helps!

I'm out!

3 0

2 years ago

Read 2 more answers

X²-12x+a=(x+b)² find a and b

Valentin [98]

Answer:

Step-by-step explanation:

x² - 12x + a = (x + b)²

x² - 12x + a = x² + 2xb + b²

-12 = 2b and a = b²

b = -6

a = b² = 36

8 0

2 years ago

Simplify the following: 6i^3 +4j^2 -6i<br> Please show work

Vadim26 [7]

Answer:

Concept: Vectors

I think the confusion here might be the usage of i and j
Just to let you know, i=x and j=y
So let's use that fact to conceptualize this
6x^3+4y^2-6x
We can simplify by applying a common factor
2(x^3+2y^2-3x)
Thats the most we can simplify this

6 0

2 years ago

Find the quotient 115.338 ÷ 2.82

MaRussiya [10]

Answer:

The quotient is 40.9

6 0

3 years ago