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GenaCL600 [577]
3 years ago
6

Help me with my help my work I really need help

Mathematics
1 answer:
BartSMP [9]3 years ago
6 0
<h2>Figure 1</h2>
  • Base Shape: Rectangular Prism/Formula: 2(wl + hl + hw)
  • Volume Formula: W × H × L

<h2>Figure 2</h2>
  • Base shape: Rectangular Prism/Formula: 2(wl + hl + hw)
  • Volume Formula: W × H × L

<h2>Figure 3</h2>
  • Base shape: Rectangular Prism/Formula: 2(wl + hl + hw)
  • Volume Formula: W × H × L

<h2>Figure 4</h2>
  • Base shape: Rectangular Prism/Formula: 2(wl + hl + hw)
  • Volume Formula: W × H × L

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What is 8.52*10 to the third power in standard notation?
MrRa [10]
AKA: 8.52x10^3=8520
^^Also Known As
6 0
3 years ago
Seven - tenths of the votes for blue were made by girls. Did girls who voted for blue make up more than or less than half of all
Ludmilka [50]

Answer:

More than half

Step-by-step explanation:

10/10 would be one whole, and half of ten is 5, which makes 5/10 equal to one half. 7 is greater than 5, so that means 7/10 is more than one half. Hope this helps!

7 0
3 years ago
you roll a fair 6-sided die. What is P ( roll a 2 )? if necessary round your answer to 2 decimal places.
xxTIMURxx [149]

Answer:

16.66%

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Laurie was completing the treasurer's report for her son's Boy Scout troop at the end of the school year. She didn't remember ho
FrozenT [24]

Answer:

14 boys paid for the full year fee and 4 boys paid for the partial year fee

Step-by-step explanation:

Create a system of equations, where x is the number that paid for the $24 fee and y is the number that paid for the $16 fee:

24x + 16y = 400

x = y + 10

Solve by substitution by plugging in y + 10 as x:

24x + 16y = 400

24(y + 10) + 16y = 400

Solve for y:

24y + 240 + 16y = 400

40y + 240 = 400

40y = 160

y = 4

Then, plug in 4 as y to find x:

x = y + 10

x = 4 + 10

x = 14

So, 14 boys paid for the full year fee and 4 boys paid for the partial year fee.

8 0
3 years ago
F(x) = lnx/x
My name is Ann [436]
f(x) = \frac{lnx}{x}

(a) f'(x) = \frac{d}{dx}[\frac{lnx}{x}]
Using the quotient rule:
f'(x) = \frac{\frac{1}{x} \cdot x - lnx}{x^{2}}
f'(x) = \frac{1 - lnx}{x^{2}}

For maximum, f'(x) = 0;
\frac{1 - lnx}{x} = 0
lnx = 1, x = e

(b) <em>Deduce:
</em>e^{x} \geq x^{e}, x > 0
<em>
Soln:</em> Since x = e is the greatest value, then f(e) ≥ f(x) > f(0)
\frac{ln(e)}{e} \geq \frac{lnx}{x}
\frac{1}{e} \geq \frac{lnx}{x}, since ln(e) is simply equal to 1

Now, since x > 0, then we don't have to worry about flipping the signs when multiplying by x.
\frac{x}{e} \geq lnx
x \geq elnx
x \geq ln(x^{e})

Taking the exponential to both sides will cancel with the natural logarithmic function in the right hand side to produce:
e^{x} \geq e^{ln(x^{e}})
e^{x} \geq x^{e}, as required.
3 0
3 years ago
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