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FinnZ [79.3K]
2 years ago
13

PLSSS HELP IF YOU TURLY KNOW THISS

Mathematics
1 answer:
geniusboy [140]2 years ago
4 0

Answer:

A

Step-by-step explanation:

\frac{4}{5} + \frac{2}{5} = \frac{6}{5} \\Simple make it improper, resulting in answer A

Hope this helps!

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John buys a new flat screen TVs for $289 the sales tax in his city is 9.5 % what is the total cost of the television with tax
WINSTONCH [101]

Answer:

$316.46

Step-by-step explanation:

total cost = 109.5% = 109.5% x $289 = $316.46 (2dp)

Topic: Percentages

If you like to venture further, please give my Instagram page a follow (learntionary). I'll be constantly posting math tips and notes! Thanks!

4 0
3 years ago
A box of cereal states that there are 96 calories in a 3/4
IgorC [24]

Answer:

112 calories per cup

Step-by-step explanation:

Let x = unit rate for calories per cup,

Then (3/4)*x = 84

and x = 84*(4/3) = 112 calories per cup

3 0
3 years ago
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8÷2(2+2). I need help finding the correct answer. 8÷2(2+2). I need help finding out if it is 1 or 16.
deff fn [24]

Answer:

The answer is 16

Step-by-step explanation:

8 divided by 2 (2+2)=16

8 0
3 years ago
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Uma is paid $12.25 for each chair she decorates. Last week she
Luda [366]

Answer:

$514.50

Step-by-step explanation:

7+4+2+8=21

$12.25x21=$514.50

6 0
3 years ago
Find the exact value of each trigonometric function for the given angle θ.
Kay [80]

Answer:

\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=\dfrac{2}{\sqrt{3}}.

Step-by-step explanation:

The given angle is 240 degrees.

We need to find the exact value of each trigonometric function for the given angle θ.

Since \theta=240, it means θ lies in 3rd quadrant. In 3d quadrant only tan and cot are positive.

\sin (240^\circ)=\sin (180^\circ+60^\circ)=-\sin (60^\circ)=-\dfrac{\sqrt{3}}{2}

\cos (240^\circ)=\cos (180^\circ+60^\circ)=-\cos (60^\circ)=-\dfrac{1}{2}

\tan (240^\circ)=\tan (180^\circ+60^\circ)=\tan (60^\circ)=\sqrt{3}

\cot (240^\circ)=\cot (180^\circ+60^\circ)=\cot (60^\circ)=\dfrac{1}{\sqrt{3}}

\sec (240^\circ)=\sec (180^\circ+60^\circ)=-\sec (60^\circ)=-2

\csc (240^\circ)=\csc (180^\circ+60^\circ)=-\csc (60^\circ)=-\dfrac{2}{\sqrt{3}}

Therefore, \sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=-\dfrac{2}{\sqrt{3}}.

8 0
3 years ago
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