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muminat
3 years ago
9

The legs of a right triangle are 3 units and 8 units. What is the length of the hypotenuse? Round your answer to the nearest hun

dredth.
Mathematics
1 answer:
Juliette [100K]3 years ago
4 0
Pythagorean Theorem
3*3+8*8=x*x
9+64=x*x
73=x*x
x=√73≈8.5
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M is the midpoint of AN, A has coordinates (-6, -6) and M has coordinates (1, 2). Find the coordinates of N.
Cloud [144]
The midpoint, M, of points A and N is (8,10) because;
Point A is (-6,-6) which has a slope of 8/7 (rise/run) with M, (1,2). So, if 8/7 is repeated/ added to M, it will be point N.
1+7=8 (run/x)
2+8=10 (rise/y)
Put x and y together to get (8,10).
N= (8,10).
5 0
2 years ago
peanuts in bulk bins at the grocery store costs $0.30 per pound how much would 2 pounds of peanuts cost
Helen [10]
$0.60 cents would be the cost of 2 lbs
8 0
3 years ago
Please help me with this and explain so I can get it. Do only 3 and 9
ASHA 777 [7]
5a+b = 5(6)+3 =3
10-r+5 = 10-(9)+5 =6
6 0
3 years ago
A radio telescope has a parabolic surface, as shown below.
krek1111 [17]
OK, so the graph is a parabola, with points x=0,y=0; x=6,y=-9; and x=12,y=0

Because the roots of the equation are 0 and 12, we know the formula is therefore of the form

y = ax(x - 12), for some a

So put in x = 6

-9 = 6a(-6)

9 = 36a

a = 1/4

So the parabola has a curve y = x(x-12) / 4, which can also be written y = 0.25x² - 3x

The gradient of this is dy/dx = 0.5x - 3

The key property of a parabolic dish is that it focuses radio waves travelling parallel to the y axis to a single point. So we should arrive at the same focal point no matter what point we chose to look at. So we can pick any point we like - e.g. the point x = 4, y = -8

Gradient of the parabolic mirror at x = 4 is -1

So the gradient of the normal to the mirror at x = 4 is therefore 1.

Radio waves initially travelling vertically downwards are reflected about the normal - which has a gradient of 1, so they're reflected so that they are travelling horizontally. So they arrive parallel to the y axis, and leave parallel to the x axis.

So the focal point is at y = -8, i.e. 1 metre above the back of the dish.
5 0
2 years ago
Evaluate the indefinite integral. (Use C for the constant of integration.) sin(10x) 1 cos2(10x) dx
Schach [20]

Answer:

The result of the integral is -\frac{\cos^3{10x}}{30} + C

Step-by-step explanation:

We are given the following integral:

\int \sin{(10x)}\cos^{2}{(10x)} dx

I am going to solve by substitution, using u = \cos{10x}, so du = -10\sin{10x}dx, dx = -\frac{du}{10\sin{10x}}. So, we have

-\frac{1}{10} \int u^2 du

Which has the following result:

-\frac{u^3}{30} + C

Going back to x, the result of the integral is

-\frac{\cos^3{10x}}{30} + C

5 0
2 years ago
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