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Dafna11 [192]
3 years ago
5

Help! With this math problem

Mathematics
1 answer:
tia_tia [17]3 years ago
8 0

Answer:

Its C

Step-by-step explanation:

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Jay was reaching into her purse and accidentally spilled her coin purse. 10 pennies fell on the floor. Jay noticed that only 2 o
kompoz [17]

Answer:

4.39%

Step-by-step explanation:

There are no marking to identify the coins, so the order is not important. Since the order not important we use combination instead of permutation.

A coin have 2 possible outcome, head or tails. Assuming the coin is fair each outcome will be 50% or 0.5 chance. If heads= A and tails =B, then the probability of 2 pennies will be:

P(A=2) = 2C10 * A^2 * B^(10-2)

P(A=2) = 10*9/2 * 0.5^2 * 0.5^8

P(A=2) = 0.0439= 4.39%

6 0
3 years ago
What fraction of the dunk tanks require at least 500 gallons of water? Write the fraction in simplest form.
Cerrena [4.2K]

Answer:

1/2

Step-by-step explanation:

Based on the information observed from the attached box and whisker plot, the Fraction of dunk tanks which requires atleast 500 gallons of water. This fractional value will be the property of plot in the position marked as 500 on the plot. The point which refers to 500 gallons on the plot is the ticked point in between the box. This point represents the median value in a box and whisker plot.

The median value represents the 50th percentile value which relates to half of the distribution. This means that fraction of dunk which requires atleast 500 gallons is : (50/100) = 1/2

7 0
3 years ago
What type of angles are 4 and 5
vodomira [7]

Answer:

option c. Alternate interior angles

6 0
3 years ago
Read 2 more answers
Factor 2x^2-10x+8 completely
LUCKY_DIMON [66]
2(x^2-5x+4) That's the smallest I see. Double check though. I might be misunderstanding the way it ways the answer.
6 0
3 years ago
Read 2 more answers
Consider the sequence defined recursively by an+1 = ( an − 1 if an ≥ 10 2an if an < 10 )
densk [106]

Answer:

a) a₁ = 14, a₂ = 13, a₃ = 12, a₄ = 11

b) an+4 = 16

c) Does not exist

Step-by-step explanation:

The last digit in student number is given as 7.

a) a₀ = 7

Since an < 10 we use 2an

Therefore a₁ = a₀₊₁ = 2 × a₀ = 2 × 7 = 14

                 a₂ = a₁₊₁ = a₁ - 1 = 14 -1 = 13

                a₃ = a₂₊₁ = a₂ - 1 = 13 -1 = 12

                a₄ = a₃₊₁ = a₃ - 1 = 12 -1 = 11

b) an = 1, we have an+1 = 2an

Therefore  an+2 = an+1+1 = 2 × 2 = 4

                 an+3 = an+2+1 = 2 × 4 = 8

                 an+4 = an+3+1 = 2 × 8 = 16

Therefore, an+4 = 16

c) If a₀ = 3, therefore a₁ = a₀₊₁ = 2×3 = 6

                                  a₂ = a₁₊₁ = 2×6 = 12

                                 a₃ = a₂₊₁ = a₂₋₁ = 12- 1 =11

                                 a₄ = a₃₊₁ = a₃₋₁ = 11- 1 =10

                                a₅ = a₄₊₁ = a₄₋₁ = 10- 1 = 9

                                a₆ = 2×9 = 18

We can therefore see that limn→[infinity] does not exist.

3 0
4 years ago
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