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Aleonysh [2.5K]
3 years ago
14

The area in square feet of a rectangular field is x2 - 140x + 4800. The width, in feet, is x-60. What is the length, in feet?

Mathematics
1 answer:
Shalnov [3]3 years ago
5 0

The length in feet is (x - 80) feet

<h3><u>Solution:</u></h3>

The area in square feet of a rectangular field is x^2 - 140x + 4800

The width, in feet, is x - 60

To find: length in feet

<em><u>The area of rectangle is given as:</u></em>

\text {area of rectangle }=\text { length } \times \text { width }

Now we can simplify area

area = x^2 - 140x + 4800

-140x can be rewritten as -80x - 60x

area = x^2 -80x -60x + 4800

Taking "x" as common from first two terms and -60 as common from last two terms

area = x(x - 80) -60(x - 80)

Taking (x - 80) as common term

Area = (x - 80)(x - 60)

Substitute area = (x - 80)(x - 60) and width = (x - 60)

(x-80)(x-60)=\text { length } \times(x-60)\\\\length = \frac{(x-80)(x-60)}{(x-60)}

Cancelling (x - 60)

length = (x - 80)

Thus the length in feet is (x - 80) feet

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