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Alex_Xolod [135]
3 years ago
13

What number is represented by 4x²+17x+2 if x=−2 or if xx=2/3?

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
5 0

Answer:

-16

15.11

Step-by-step explanation:

We are given an expression which is a function of x and it is 4x² + 17x + 2 ...... (1)

We have to find the number which is represented by the above expression when x= -2 or when x= 2/3.

For, x= -2, putting  -2 in place of x in the expression (1), we get

4(-2)² + 17(-2) +2 =16 -34 +2= -16 (Answer)

For, x=  2/3, putting  2/3 in place of x in the expression (1), we get

4(2/3)² +17(2/3) +2 = 15.11 (Answer)

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Soit trois nombres consécutifs. Lorsque l’on soustrait le double du deuxième nombre du quadruple du
irina [24]

Answer:

Les trois nombres sont 5, 6 et 7.

Step-by-step explanation:

Soit x le premier nombre.

x + 1 sera le second et x + 2 sera le troisième.

On pose l'équation :

2x + 3(x + 1) = 4(x + 2)

2x + 3x + 3 = 4x + 8

5x - 4x = 8 - 3

x = 5

4 0
3 years ago
Una persona camina 7 kilómetros hacia el norte, después 3 kilómetros hacia el este y, luego, 3 kilómetros hacia el sur. ¿A qué d
qaws [65]

Answer:

La persona está a 5 kilómetros con respecto al punto de partida.

Step-by-step explanation:

Considérese que la dirección norte coincide con el semieje +y y que la dirección este coincide con el semieje +x. A continuación, obtenemos las formas vectoriales equivalentes de cada afirmación:

(i) Una persona camina 7 kilómetros hacia el norte:

\vec r_{1} = 7\,\hat{j}\,[km]

(ii) Después 3 kilómetros hacia el este:

\vec r_{2} = 3\,\hat{i}\,[km]

(iii) Y luego, 3 kilómetros hacia el sur:

\vec r_{3} = -3\,\hat{j}\,[km]

El vector resultante de desplazamiento se construye a partir de la siguiente suma de vectores:

\vec R = \vec r_{1}+\vec r_{2} + \vec r_{3} (1)

\vec R = 3\,\hat{i} + 4\,\hat{j}\,[km]

Asumiendo que la distancia coincide con el desplazamiento resultante, calculamos la distancia con respecto al punto de partida mediante el Teorema de Pitágoras:

\|\vec R\| = \sqrt{3^{2}+4^{2}}

\|\vec R\| = 5\,km

La persona está a 5 kilómetros con respecto al punto de partida.

3 0
2 years ago
Suppose that a spherical droplet of liquid evaporates at a rate that is proportional to its surface area: where V = volume (mm3
Alex

Answer:

V = 20.2969 mm^3 @ t = 10

r = 1.692 mm @ t = 10

Step-by-step explanation:

The solution to the first order ordinary differential equation:

\frac{dV}{dt} = -kA

Using Euler's method

\frac{dVi}{dt} = -k *4pi*r^2_{i} = -k *4pi*(\frac {3 V_{i} }{4pi})^(2/3)\\ V_{i+1} = V'_{i} *h + V_{i}    \\

Where initial droplet volume is:

V(0) = \frac{4pi}{3} * r(0)^3 =  \frac{4pi}{3} * 2.5^3 = 65.45 mm^3

Hence, the iterative solution will be as next:

  • i = 1, ti = 0, Vi = 65.45

V'_{i}  = -k *4pi*(\frac{3*65.45}{4pi})^(2/3)  = -6.283\\V_{i+1} = 65.45-6.283*0.25 = 63.88

  • i = 2, ti = 0.5, Vi = 63.88

V'_{i}  = -k *4pi*(\frac{3*63.88}{4pi})^(2/3)  = -6.182\\V_{i+1} = 63.88-6.182*0.25 = 62.33

  • i = 3, ti = 1, Vi = 62.33

V'_{i}  = -k *4pi*(\frac{3*62.33}{4pi})^(2/3)  = -6.082\\V_{i+1} = 62.33-6.082*0.25 = 60.813

We compute the next iterations in MATLAB (see attachment)

Volume @ t = 10 is = 20.2969

The droplet radius at t=10 mins

r(10) = (\frac{3*20.2969}{4pi})^(2/3) = 1.692 mm\\

The average change of droplet radius with time is:

Δr/Δt = \frac{r(10) - r(0)}{10-0} = \frac{1.692 - 2.5}{10} = -0.0808 mm/min

The value of the evaporation rate is close the value of k = 0.08 mm/min

Hence, the results are accurate and consistent!

5 0
3 years ago
3m-5p=12 solve for p
umka21 [38]
3m - 5p = 12

3m(-3m) -5p = (-3m)+ 12
-5p = -3m + 12
(-5)/-5p = (-5)/ (-3m + 12)
p = 3/5m + 12/-5
5 0
3 years ago
Read 2 more answers
How to Simplify (x-2)(3x2 + 3x + 2) to a polynomial in standard form:
swat32
Answer: 3x^3 - 3x^2 - 4x - 4

Explanation:

(x - 2)(3x^2 + 3x + 2)

= x(3x^2 + 3x + 2) - 2(3x^2 + 3x + 2)

= 3x^3 + 3x^2 + 2x - 6x^2 - 6x - 4

= 3x^3 - 3x^2 - 4x - 4
6 0
2 years ago
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