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mixas84 [53]
2 years ago
12

2. One important factor in inventory control is the variance of the daily demand for a product. Management believes that demand

is normally distributed with the variance equal to 250. In an experiment to test this belief about , the daily demand was recorded for 25 days. The data has been summarized as follows: xbar = 50.6 and s2 = 500 Do the data provide sufficient evidence to show that management's belief about the variance is untrue? (Use alpa=0.01 ).
Mathematics
1 answer:
salantis [7]2 years ago
4 0

Answer:

we reject H0 and conclude that management's belief about variance is untrue.

Step-by-step explanation:

H0 : σ² = 250

H1 : σ² ≠ 250

Sample size, n = 25

xbar = 50.6 ; s² = 500

α = 0.01 ;

The test statistic :

χ² = [(n - 1)s²] ÷ σ²

χ² = [(25 - 1)* 500] ÷ 250

χ² = (24 * 500) / 250

χ² = 12000 / 250

χ² = 48

The critical value:

df = n-1 ; 25 - 1 = 24

χ²(0.01/2 ; 24) = 45.559

Decison :

Reject H0 : if |χ² statistic| > critical value

Since 48 > 45.559

Hemce, we reject H0 and conclude that management's belief about variance is untrue.

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Step-by-step explanation:

Assume that adults have IQ scores that are normally distributed with a mean of mu equals μ = 105 and a standard deviation sigma equals σ = 15

We need to find the probability that a randomly selected adult has an IQ less than 135

For the probability that X < b;

  • Convert b into a z-score using z = (X - μ)/σ, where μ is the mean and σ is the standard deviation
  • Use the normal distribution table of z to find the area to the left of the z-value ⇒ P(X < b)

∵ z = (X - μ)/σ

∵ μ = 105 , σ = 15 and X = 135

∴ z=\frac{135-105}{15}=2

- Use z-table to find the area corresponding to z-score of 2

∵ The area to the left of z-score of 2 = 0.97725

∴ P(X < 136) = 0.97725

The probability that a randomly selected adult has an IQ less than

135 is 0.97725

Learn more:

You can learn more about probability in brainly.com/question/4625002

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2 years ago
Find AE if AB=12, AC=16, and ED=5.
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Answer:

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If m∠F = 90° and m∠G = 70°, then ∠F and ∠G are not supplementary.
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a) Proof by contradiction is different from traditional proof as it accepts a single example showing that a statement is false, instead of having the need to derive a general relationship for all input values.

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<h3>What are supplementary angles?</h3>

Two angles are called supplementary angles if the sum of their measures has a value of 180º.

The measures of the angles in this problem are given as follows:

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Then the sum of the measures of this angles is given as follows:

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Which is a different sum of 160º, confirming the statement that the angles are not supplementary by contradiction.

A similar problem, involving proof by contradiction and supplementary angles, is presented at brainly.com/question/28889480

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Answer the following questions given the ordered pairs below. {(-5,0). (-3,2), (0,4), (2-7)} a) what is the domain? b) What is t
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