Y≤x/3-1 AND y≤x/3-3
So for BOTH inequalities to be true:
y≤x/3-3
Answer:
A.16–i is correct.
Step-by-step explanation:
(4+i)(4–i). [(a+b)(a–b)=(a²–b²)]
(4²–i²)=16–i
I hope this answer is correct so please vote my answer
Perform the indicated multiplications...
12x*x+12x*2-5*2x-5*(-1)
12x^2+24x-10x+5 combine like terms
12x^2+14x+5
No. AB is not perpendicular to AC
There are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned from 14 volunteers.
Given that a school dance committee has 14 volunteers and each dance requires 3 volunteers at the door, 5 volunteers on the floor and 6 on floaters.
We are required to find the number of ways in which the volunteers can be assigned.
Combinations means finding the ways in which the things can be choosed to make a new thing or to do something else.
n
=n!/r!(n-r)!
Number of ways in which the volunteers can be assigned is equal to the following:
Since 2 have not been assigned so left over volunteers are 14-2=12 volunteers.
Number of ways =14
=14!/12!(14-12)!
=14!/12!*2!
=14*13/2*1
=91 ways
Hence there are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned.
Learn more about combinations at brainly.com/question/11732255
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