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Annette [7]
2 years ago
11

I need help please ​

Mathematics
1 answer:
navik [9.2K]2 years ago
4 0

Answer: B

Step-by-step explanation: the values start from zero to higher

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Your teacher announced a 50-point math quiz for tomorrow. The quiz will have 15 questions with word problems worth 4 points each
koban [17]

Answer:

5  word problems(4points each)      &      10 open (3 points each)

Step-by-step explanation:

O= open response

W= word problems

  W+O =15

4W + 3O = 50

multiply the first by -3 to eliminate O

-3W -3O = -45

4W  + 3O = 50

  AD BOTH

W = 5    ( 5 questions word problems)

O= 10   ( 10 questions open response)

  5x4 = 20

10x3 = 30

      20 + 30 = 50 points

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2 years ago
Is reading a book that is 1400 pages he will read the same number of pages each day if he reads the book in 7 days how many page
Alex777 [14]
He will read 200 pages a day because 1400/7 = 200
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2 years ago
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Surface area of a cylinder. (see attached image please)
Zolol [24]

Answer:

\large{ \tt{❃ \: EXPLANATION}} :

  • Firstly you need to remember the formula to find out surface area of a cylinder - Surface area of a cylinder = 2πr ( r + h ) where r is the radius of a circular face and h is the height of the cylinder.

  • We're provided : Diameter of cylinder = 12 which means radius ( r ) = 6 cm [ Radius is the half of diameter ] & Height ( h ) = 25 cm & we know pi ( π ) = 22/7.

\large{ \tt{❁ \: LET'S \: SOLVE}} :

\large{\boxed{  \tt{☄TOTAL \: SURFACE \: AREA \: OF\: CYLINDER= 2\pi \: r \: ( \: r + h)}}}

- Plug the values & then simplify !

\large{↦2 \times  \frac{22}{7}  \times 6(6 + 25) }

\large{↦2 \times  \frac{22}{7}   \times 6 \times 31}

\boxed{\large{↦1169.14  \: \tt{ {cm}^{2} }}}

  • Hence , The surface area of given cylinder is 1169.14 cm²

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5 0
2 years ago
Dimitrius returned 5 library books last week, returned 3 books this week, and then checked out 8 more books. He now has 12 libra
dimulka [17.4K]
Totally he had 12 books before last week.
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I need help on my math homework how do I get help?
Fiesta28 [93]
Simply post the picture of the equation with a bit of information you think is needed. or write down the equation and post it !
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