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2 years ago

Fill in the blank to complete each statement.

Biology

1 answer:

DiKsa [7]2 years ago

5 0

5. Seasons

6. Rotation

7. Eclipse

8. Year

9. Calander

10. Vernal equinox

Let me know if this helped! Have a great day.

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Please help!! A light-year is about _____. 6 million miles 6 million kilometers 6 billion miles 6 trillion miles none of the abo

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The answer would be 6 billion

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3 years ago

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What is the allele frequency?

Keith_Richards [23]

Allele frequency is a measure of the relative frequency of an allele on a genetic locus in a population.

Usually it is expressed as a proportion or a percentage.

In population genetics, allele frequencies show the genetic diversity of a species population or equivalently the richness of its gene pool.

The frequencies of all the alleles of a given gene often are graphed together as an allele frequency distribution histogram.

Population genetics studies the different "forces" that might lead to changes in the distribution and frequencies of alleles - in other words, to evolution.

Besides selection, these forces include genetic drift, mutation and migration.

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3 years ago

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Each heredity trait corresponds to ___ ?

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a sequence of nitrogen bases

Explanation:

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3 years ago

Which descriptions apply to prokaryotic cells? Check all that apply.

tester [92]

Answer:

1. Are usually single-celled.

2. Do not contain membrane-bound organelles

3. Have DNA located in cytoplasm

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Prokaryotic cells are single-celled organisms which have the following characters:

1. They lack a true nucleus and hence, they do not have their genetic material enclosed in a nuclear membrane-bound nucleus, rather it is present in the cytoplasm.

2. They lack all the membrane-bound organelles such as mitochondria, endoplasmic reticulum, etc.

3. They are usually. very small in size and hence are microscopic.

Examples include all the bacterias.

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3 years ago

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In 1985 a biologist counted 750 pine trees in a 250 hectare forest. Using similar counting techniques, the biologist counted 1,2

Alisiya [41]

Answer:

Suppose that we have a given function f(x)

The average rate of change of the function between two values x₁ and x₂ is given by:

$r = \frac{f(x_2) - f(x_1)}{x_2 - x_1}$

a) We want to find the average (rate) of change on the size of population from 1985 to 1995.

We have that:

f(1985) = 750

f(1995) = 1500

Then we have:

$r = \frac{1500 - 750}{1995 - 1985} = 750/10 = 75$

This means that the population of trees increases, in average, at a rate of 75 trees per year.

b) What is the density of trees each year that they were counted?

This will be equal to the quotient between the number of trees and the area.

1985: number of trees = 750 pines

area = 250 ha

Then the density is:

D(1985) = (750 pines)/(250 ha) = 3 pines/ha

So 1985, there were 3 pines per hectare.

1990: number of trees = 1250 pines

area = 250 ha

Then the density is:

D(1990) = (1250 pines)/(250 ha) = 5 pines/ha

1995: number of trees = 1500 pines

area = 250 ha

The density is:

D(1995) = (1500 pines)/(250 ha) = 6 pines/ha

3) now we want to get the average change between 1985 and 1995 in the density, this will be:

$r = \frac{D(1995) - D(1885)}{1995 - 1985} = \frac{6 pines/ha - 3pines/ha}{10} = 0.3 pines/ha$

So, on average, each year the number of pines per hectare increases by 0.3

7 0

3 years ago

Fill in the blank to complete each statement.​

Fill in the blank to complete each statement.