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A hardware store receives a shipment of bolts that are supposed to be 12 cm long. The mean is indeed 12 cm, and the standard dev

Yuliya22 [10]

Answer: 0.9104

Step-by-step explanation:

Given : A hardware store receives a shipment of bolts that are supposed to be 12 cm long.

Mean : $\mu=12\text { cm}$

Standard deviation : $\sigma= 0.2\text{ cm}$

Sample size : n=10

Since, they will declare the shipment defective and return it to the manufacturer if the average length of the 100 bolts is less than 11.97 cm or greater than 12.04 cm.

So for the shipment to be satisfactory, the length of the bolts must be between 11.97 cm and 12.04 cm.

We assume that the length of the bolts are normally distributed.

Let X be the random variable that represents the length of randomly picked bolt .

For Z score : $z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

For x = 11.97

$z=\dfrac{11.97-12}{\dfrac{0.2}{\sqrt{100}}}=-1.5$

For x = 12.04

$z=\dfrac{12.04-12}{\dfrac{0.2}{\sqrt{100}}}=2$

By using the standard normal distribution table , the probability that the shipment is found satisfactory will be :-

$P(511.97$

Hence, the probability that the shipment is found satisfactory=0.9104

3 0

3 years ago

The quotient of a number and negative eight is five-eighths. Find the number.

max2010maxim [7]

Answer:

-64/5

Step-by-step explanation:

Basically, the word "quotient" means the answer to a division problem. Therefore, its a division problem, so you have to work backwards with multiplication. -8 times a number is 5/8, so the other number is going to be negative.

The number is -64/5

5 0

2 years ago

Read 2 more answers

A commuter must pass through 5 traffic lights on her way to work and will have to stop at each one that is red. She estimates th

sergij07 [2.7K]

Answer:

(a) The mean or expected value of X is 2.2.

(b) The standard deviation of X is 1.3.

Step-by-step explanation:

Let X = number of times the traffic light is red when a commuter passes through the traffic lights.

The probability distribution of X id provided.