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GuDViN [60]
3 years ago
14

A stunt driver rounds a banked, circular curve. The driver rounds the curve at a high, constant speed, such that the car is just

on the verge of skidding to the outside of the curve. Which forces are directly responsible for producing the car's centripetal acceleration? a. centripetal force b. Coriolis force c. normal force d. frictional force e. gravitational force
Physics
1 answer:
Sladkaya [172]3 years ago
7 0

Answer:

option C and D

Explanation:

When a stunt driver is rotating on the banked road the force which is responsible for the centripetal acceleration of the car is Frictional force and the Normal Force.

The Frictional force component of the banked road will protect the car from skidding.

And the normal force component will protect the car from toppling inward due to centripetal force acting on it.

Hence, the correct answer is option C and D

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there are diffrent species of aloe vera so there is
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3 years ago
A wad of clay of mass m1 = 0.49 kg with an initial horizontal velocity v1 = 1.89 m/s hits and adheres to the massless rigid bar
notka56 [123]

Answer:

<h2>The angular velocity just after collision is given as</h2><h2>\omega = 0.23 rad/s</h2><h2>At the time of collision the hinge point will exert net external force on it so linear momentum is not conserved</h2>

Explanation:

As per given figure we know that there is no external torque about hinge point on the system of given mass

So here we will have

L_i = L_f

now we can say

m_1v_1\frac{L}{2} = (m_2L^2 + m_1(\frac{L}{2})^2)\omega

so we will have

0.49(1.89)(0.45) = (2.13(0.90)^2 + 0.49(0.45)^2)\omega

\omega = 0.23 rad/s

Linear momentum of the system is not conserved because at the time of collision the hinge point will exert net external force on the system of mass

So we can use angular momentum conservation about the hinge point

6 0
3 years ago
Which of these is NOT a common building material?
Over [174]
B Quartz. Will be your answer of thia
8 0
3 years ago
Read 2 more answers
A 77.0 kg woman slides down a 42.6 m long waterslide inclined at 42.3. at the bottom, she is moving 20.3 m/s.how much work did f
zhuklara [117]

Answer:

5.791244495 KNm

Explanation:

The height h is given by, h=42.6sin42.3^{o}

Potential energy, PE is given by

PE=mgh where m is mass of the woman, g is acceleration due to gravity whose value is taken as 9.81 m/s^{2} and h is already given hence substituting 77 Kg for m we obtain

PE=77*9.81*42.6sin42.3^{o}=21656.7095 Nm

PE=21.6567095 KNm

We also know that Kinetic energy is given by0.5mv^{2} where v is the velocity and substituting v for 20.3 we obtain

KE=0.5*77*20.3^{2}=15865.465 Nm

KE=15.865465 KNm

Friction work is the difference between PE and KE hence

Friction work=21.6567095 KNm-15865.465 Nm=5.791244495 KNm

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3 years ago
Describe how energy from the sun interact with substances
bagirrra123 [75]

Answer:

substances will move faster and become warm to the touch.

Explanation:

when the radiation from the sun comes down and hits substances, the substances absorbs the radiation making them warm. the absorbed energy is transformed into heat energy. this heat energy plays an important role in regulating the temperature of the Earths crust, surface waters, and low atmosphere.

7 0
4 years ago
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