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olya-2409 [2.1K]
3 years ago
6

Once precipitation has fallen on land what paths are available to it

Physics
1 answer:
zhenek [66]3 years ago
5 0
When water falls on land, there are several different paths that are available for it. It can evaporate back into the atmosphere, go into rivers, streams or lakes, it can sink into the ground so therefore, downward and laterally.
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A hiker walks 20.51 m at 33.16 degrees. What is the Y component of his displacement?
Serhud [2]

Answer:

<em>The y component of his displacement is 11.22 meters</em>

Explanation:

<u>Components of the displacement</u>

The displacement is a vector because it has a magnitude and a direction. Let's suppose a displacement has a magnitude r and a direction θ, measured with respect to the positive x-direction. The horizontal component of the displacement is calculated by:

x=r\cos\theta

The vertical component is calculated by:

y=r\sin\theta

The hiker has a displacement with magnitude r = 20.51 m at an angle of 33.16 degrees. Substituting in the above equation:

y=20.51\sin(33.16^\circ)

y=11.22\ m

The y component of his displacement is 11.22 meters

7 0
3 years ago
A boat has a mass of 7660 kg. Its engines generate a drive force of 4080 N due west, while the wind exerts a force of 680 N due
makvit [3.9K]

Answer:

0.29 m/s due west.

Explanation:

According to newton's second law,

Net force acting on an object = mass×acceleration

From the question,

F+F₁+F₂ = ma................ Equation 1

Where F = The force generated from the engine, F₁ = Force exerted by the wind, F₂ = Force exerted due to the water, m = mass of the boat, a = acceleration of the boat.

Given: F = 4080 N , F₁ = -680 N(east), F₂ = -1160 N(east). m = 7660 kg

substitute into equation 1

4080-680-1160 = 7660(a)

2240 = 7660a

Therefore,

a = 2440/7660

a = 0.29 m/s due west.

8 0
3 years ago
How long would this acceleration last
Aleksandr-060686 [28]
It would last as long as the applied force continued, or until the accelerating object hit something.
6 0
3 years ago
Optical astronomers need a clear, dark sky to collect good data. Explain why radio astronomers have no problem observing in the
gregori [183]

Answer:

In the clarification portion elsewhere here, the definition of the concern is mentioned.

Explanation:

So like optical telescopes capture light waves, introduce it to concentrate, enhance it, as well as make it usable through different instruments via study, so radio telescopes accumulate weak signal light waves, introduce that one to focus, enhance it, as well as make this information available during research. To research naturally produced radio illumination from stars, galaxies, dark matter, as well as other natural phenomena, we utilize telescopes.

Optical telescopes detect space-borne visible light. There are some drawbacks of optical telescopes mostly on the surface:

  • Mostly at night would they have been seen.
  • Unless the weather gets cloudy, bad, or gloomy, they shouldn't be seen.

Although radio telescopes monitor space-coming radio waves. Those other telescopes, when they are already typically very massive as well as costly, have such an improvement surrounded by optical telescopes. They should be included in poor weather and, when they travel through the surrounding air, the radio waves aren't obscured by clouds. Throughout the afternoon and also some at night, radio telescopes are sometimes used.

3 0
3 years ago
The image shows the electric field lines around two charged particles.
DENIUS [597]
It's either 3 or 4 I know this becuase I have read a book about electricity
8 0
3 years ago
Read 2 more answers
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