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olya-2409 [2.1K]
4 years ago
6

Once precipitation has fallen on land what paths are available to it

Physics
1 answer:
zhenek [66]4 years ago
5 0
When water falls on land, there are several different paths that are available for it. It can evaporate back into the atmosphere, go into rivers, streams or lakes, it can sink into the ground so therefore, downward and laterally.
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Which of the following varies as the electric current varies? The magnetic force decreases The magnetic properties are varied Th
Paladinen [302]
The magnetic properties are varied
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4 years ago
What would a sound wave do if it traveled from a gas to a
NeTakaya

Answer:

speed up

Explanation:

it's sound, not electromagnetic

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3 years ago
Is an aquarium a system ?
sweet [91]

No

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6 0
3 years ago
If a spacecraft in earth orbit is pushed by a thruster what will happen?
grin007 [14]

For the orbital speed of a spacecraft we know that

v = \sqrt{\frac{GM}{r}}

here

M = mass of the planet around which satellite is revolving

r = orbital radius

Now when thruster is used by the spacecraft its speed will change due to which orbital speed will change.

Since here while changing the speed mass of the planet will be same

we can say the speed of the spacecraft will changed by thruster due to which its orbital radius will change

so the correct answer must be

<em>b. the spacecraft will change motion and will maintain this new orbit until the thruster is fired again.</em>

8 0
3 years ago
A 9,900 kg object feels a gravitational force of 12 N due to a 52,000 kg object. What is the distance between the
aleksley [76]

Answer:

0.05 m

Explanation:

From the question given above, the following data were obtained:

Mass of first object (M1) = 9900 kg

Gravitational force (F) = 12 N

Mass of second object (M2) = 52000 kg

Distance apart (r) =?

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Thus, we can obtain the distance between the two objects as shown below:

F = GM1M2/r²

12 = 6.67×10¯¹¹ × 9900 × 52000 /r²

Cross multiply

12 × r² = 6.67×10¯¹¹ × 9900 × 52000

Divide both side by 12

r² = (6.67×10¯¹¹ × 9900 × 52000)/12

Take the square root of both side

r = √[(6.67×10¯¹¹ × 9900 × 52000)/12]

r = 0.05 m

Therefore, the distance between the two objects is 0.05 m

3 0
3 years ago
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