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olya-2409 [2.1K]
4 years ago
6

Once precipitation has fallen on land what paths are available to it

Physics
1 answer:
zhenek [66]4 years ago
5 0
When water falls on land, there are several different paths that are available for it. It can evaporate back into the atmosphere, go into rivers, streams or lakes, it can sink into the ground so therefore, downward and laterally.
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A 3.0-kg brick rests on a perfectly smooth ramp inclined at 34° above the horizontal. The brick is kept from sliding down the pl
Firdavs [7]

Answer:

d=0.137 m ⇒13.7 cm

Explanation:

Given data

m (Mass)=3.0 kg

α(incline) =34°

Spring Constant (force constant)=120 N/m

d (distance)=?

Solution

F=mg

F=(3.0)(9.8)

F=29.4 N

As we also know that

Force parallel to the incline=FSinα

F=29.4×Sin(34)

F=16.44 N

d(distance)=F/Spring Constant

d(distance)=16.44/120

d(distance)=0.137 m ⇒13.7 cm

4 0
3 years ago
What two elements are used with other metals to lower their melting points?
vampirchik [111]

Answer:

C) antimony and bismuth

Explanation:

6 0
3 years ago
Read 2 more answers
A person travels by car from one city to an-
Mademuasel [1]
<h2>Answer:</h2>

<h2>Explanation:</h2>

First, let's refer to the distance formula:

d=v*t, where d is distance, v is velocity or speed and t is time.

Now, let's find the distance covered by each individual speed that the car had:

<h3>1. Speed 1.</h3>

In order to use the formula, we need to convert minutes into hours since the speed is given in km/h.

21.1 min/60= 0.35 h.

Now, apply the distance formula.

d=(0.35h)*(86.8km/h)= 30.38 km.

<h3>2. Speed 2.</h3>

Convert minutes to hours again and do the same calculations.

10.6min/60=0.18h

d=(0.18h)*(106km/h)= 19.08 km.

<h3>3. Speed 3.</h3>

36.5min/60= 0.61h

d=(0.61h)*(30.9km/h)= 18.85 km.

<h3>4. Obtain the total distance.</h3>

The total distance must be given by the addition of all individual distances traveled by the car on each speed:

Total distance= 30.38 km + 19.08 km + 18.85 km= 68.31 km.

5 0
2 years ago
Problem 1: Problem 1.58 in Young &amp; Freedman A plane leaves the airport in Galisteo and flies 170 km at 68.0° east of north;
Maurinko [17]

Answer:

Explanation:

We shall convert the displacement in vector form using unit vector i and j

consider east as x axis and north as y axis

170 km at 68.0° east of north

D₁ = 170 sin68 i + 170cos 68 j

= 157 i + 63.68 j

230 km at 36.0° south of east

D₂ = 230 cos36 i - 230 sin 36 j

= 186 i - 135.2 j

Resultant Displacement = D₁ +D₂

= 157 i + 63.68 j  + 186 i - 135.2 j

= 343 i  - 71.52 j

Resultant magnitude

= √ ( 343² + 71.52²

= 350 km

Angle

= tan⁻¹ ( - 71.52 / 343 )

12⁰ south of east .

4 0
3 years ago
A simple pendulum makes 120 complete oscillations in 3.00 min at a location where g 5 9.80 m/s2. Find (a) the period of the pend
choli [55]

Answer:

(a) 1.5 second

(b) 0.56 m

Explanation:

Pendulum makes 120 oscillations in 3 min that means in 180 seconds

time taken by the pendulum to complete one oscillation is called time period.

(a) So, the time period is 180 / 120 = 1.5 second

T = 1.5 second

Thus, the time period of the pendulum is 1.5 second.

(b) g = 9.8 m/s^2

The formula for the time period is given by

T =2\pi \sqrt{\frac{L}{g}}

Where, L be the length of pendulum

1.5 =2\times 3.14 \sqrt{\frac{L}{9.8}}

0.057= {\frac{L}{9.8}}

L = 0.56 m

Thus, the length of the pendulum is 0.56 m .

6 0
3 years ago
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