All categories

2 years ago

How are analog and digital signals similar? Check all that apply.

Physics

2 answers:

MArishka [77]2 years ago

5 0

Answer:

Both transmit data or information.

Both get weaker when traveling long distances.

Anika [276]2 years ago

5 0

Answer:

Both transmit data or information.

Both get weaker when traveling long distances.

Explanation:

Just did it on Ed. ^^

You might be interested in

What caused magnetic fields? What happens If you keep breaking a magnet in two until you reach a single atom?

mote1985 [20]

magnetic materials will produce magnetic field near it

All magnets are made up of small magnet type atoms which are known as domains

These all atoms will align itself so that they all produce strong magnetic field along the axis

this magnetic field will become more strong as more number of atoms are aligned.

Now if we break the magnet into small piece then the magnetic field strength will start decreasing and at the end when only one atom will remain then the magnetic field strength will reduce to the field of one atom only.

6 0

3 years ago

The electric company charges $0.08/kilowatt-hour. If a 2 kilowatt appliance is run for 3hours, how much will you have to pay to

asambeis [7]

Answer:

$ 0.48

Explanation:

We can calculate this quantity easily using successive products and taking into account the units.

$\frac{0.08}{kw*h}*2[kw]*3[hr]\\ \\=0.48$

The amount is $ 0.48

3 0

2 years ago

A ball is dropped from rest from a height h above the ground. another ball is thrown vertically upwards from the ground at the i

Darya [45]

The position of the first ball is

$y_1=h-\dfrac g2t^2$

while the position of the second ball, thrown with initial velocity $v$ , is

$y_2=vt-\dfrac g2t^2$

The time it takes for the first ball to reach the halfway point satisfies

$\dfrac h2=h-\dfrac g2t^2$

$\implies\dfrac h2=\dfrac g2t^2$

$\implies t=\sqrt{\dfrac hg}$

We want the second ball to reach the same height at the same time, so that

$\dfrac h2=v\sqrt{\dfrac hg}-\dfrac g2\left(\sqrt{\dfrac hg}\right)^2$

$\implies h=2v\sqrt{\dfrac hg}-g\left(\dfrac hg\right)$

$\implies h=v\sqrt{\dfrac hg}$

$\implies v=\sqrt{hg}$

8 0

3 years ago

A piece of silicon sample has a resistivity of 0.1 ω.Cm. Its thickness is 100µm. The electron mobility is 1350cm 2 v -1sec-1. Wh

lawyer [7]

The answer is Rh = 135 cm^3 and B = 0.05185 wh/m^2

Explanation:

Resitivity of silicon = 0.1

thickness = 100um

so, I = ma

Required to find out concentration of electron , we know that

Rh = up

By putting in the values,

Rh = 1350 x 0.1

Rh = 135 cm^3

Now consider,

Rh = 1 / Rh.q

= 1 / Rh . q

= 1 / 135 x1.609 x10^-19

= 4.6037 x 10^16 / cm^3

Vh = BIRh / w

B = Vh w/ IRh

B = -70 x10^-6 x 100 x10^-6 / 1x 10^-3 x 135 x 10^-6

B = 0.05185 wh / m^2

5 0

3 years ago

How large an expansion gap should be left between steel railroad rails if they may reach a maximum temperature 40.0°C greater th

ella [17]

Answer:

19.68 × 10⁻³ m

Explanation:

Given;

Original Length, L₁ = 41.0 m

Temperature Change, ΔT = 40.0°C

Thermal Linear expansion of steel is given to be, ∝ $_{steel}$ = 12 × 10⁻⁶ /°C

Generally, Linear expansivity is expressed as;

∝ = ΔL / L₁ΔT

Where

∝ is the Linear expansivity

ΔL is the change in length, L₂ - L₁

L₂ is the final length

L₁ is the original length

ΔT is the change in temperature θ₂ - θ₁ (Final Temperature - Initial Temperature)

From equation of linear expansivity

ΔL = ∝ $_{steel}$ L₁ΔT

ΔL = 12 × 10⁻⁶ /°C × 41.0 m × 40.0 °C

ΔL = 19.68 × 10⁻³ m

ΔL = 19.68 mm

8 0

3 years ago